Master production schedule, Mechanical Engineering

Assignment Help:

Master Production Schedule:

A manufacturing unit produces two products M and N on generates to stock basis. The estimated demand for the product M and N over the next six week are illustrated in the following Tables (a) and (b).

Table (a) : Demands for Product M from All Sources

 

2027_Master Production Schedule1.png

The amount for the safety stock for product M is 50 and for product N is 40. The fixed lot size for M is equal to 70 and for N are 80. The starting inventory for M is 90 and for N are 70. Make a Master Production Schedule (MPS) for the product M and N.

Solution

For both of products M and N, take the total demands, consider straining inventory, determine in which weeks ending inventory would fall below the safety stock and therefore require production and schedule a lot of the product to be generates during those weeks.

Table (c): Master Production Schedule (Number of Product M and N)

 

1787_Master Production Schedule2.png

In week 1, the balance exceeds the wanted safety stock; thus no production of product M is needed.

In week 2, the balance is also adequate to provide the desired safety stock and no production of product M is needed.

In week 3, the balance would be negative in fact if production of M where not scheduled thus a fixed lot size of 70 product M is scheduled in third week.

In week 4, the balance would actually be negative if production of M where not scheduled thus a fixed lot size of 70 product M is scheduled in fourth week.

In week 5, actually the balance would be negative if production of M where not scheduled hence a fixed lot size of 70 product M is scheduled in fifth week.

In week 6, the balance would be negative actually if production of M where not scheduled hence a fixed lot size of 70 product M is scheduled in sixth week.     

Table (e) : MPS for Product N

2478_Master Production Schedule3.png

In week 1, the balance exceeds the wanted safety stock; therefore no production of product N is needed.

In week 2, the balance would actually be negative if production of N where not scheduled hence a fixed lot size of 80 product N is scheduled in second week.

In week 3, the balance is also sufficient to provide the desired safety stock and no production of product N is needed.

In week 4, actually the balance would be negative if production of N where not scheduled hence a fixed lot size of 80 product N is scheduled in fourth week.

In week 5, the balance would actual negative if production of N where not scheduled hence a fixed lot size of 80 product N is scheduled in fifth week.

In week 6, the balance would actual negative if production of N where not scheduled hence a fixed lot size of 80 product N is scheduled in sixth week.


Related Discussions:- Master production schedule

Hydrostatic law, validity on compressible and incompressible fluids

validity on compressible and incompressible fluids

Bond, What is bond and the types..

What is bond and the types..

calculate the arc-belt length-distance and ratio , A powered metal-working...

A powered metal-working crank press (a generic press is shown at the end) has been designed to be capable of punching blanks from mild steel sheet up to 3 mm thick. 1. the ultim

CO2 welding-equipment, CO 2 WELDING CO 2 welding is one of the variat...

CO 2 WELDING CO 2 welding is one of the variations of t he GMAW (Gas Met al Arc Welding) process which is now used for welding most structural and alloy steels. The operating

Calculate the magnitude and position of the balance mass, The four masses m...

The four masses m1, m2, m3 and m4 having their radii of rotation as 200mm, 250mm, 150mm, 250mm and 300mm are 200kg, 300kg,240kg and 260kg in magnitude respectively. The angles betw

Calculate the angular acceleration of the pulleys, Calculate the angular ac...

Calculate the angular acceleration of the pulleys: The compound pulley system has a mass of 30 kg and a radius of gyration of 450 mm. Calculate the tension in each cord and th

Tunnels and laying of track, Tunnels: Tunnels become unavoidable for ...

Tunnels: Tunnels become unavoidable for negotiating hills, where detours are costly. The tunnels in rock are not lined, but those in loose strata require a lining of cement c

Find out the maximum and minimum bending stress in beam, Q.  A steel bar 10...

Q.  A steel bar 10 cm broad and 8 mm thick is subjected to bending moment. The radius of the neutral surface is 100 cm. Found out the maximum and minimum bending stress in beam.

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd