mass marketing, Mathematics

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Determine the range of given algorithm, The division algorithm says that wh...

The division algorithm says that when a is divided by b, a unique quotient and remainder is obtained. For a fixed integer b where b ≥ 2, consider the function f : Z → Z given by f(

What is the length of one side of the square, The area of a square is 64 cm...

The area of a square is 64 cm 2 . What is the length of one side of the square? To find out the area of a square, you multiply the length of a side through itself, because all

Highest common factor (hcf), We know that a factor is a quantity whic...

We know that a factor is a quantity which divides the given quantity without leaving any remainder. Similar to LCM above we can find a highest common factor (HCF)

The coordinate axes, Trace the curve y 2 = (x + 2) 2 (x - 6). Clearly sta...

Trace the curve y 2 = (x + 2) 2 (x - 6). Clearly state all the properties you have used for tracing it(e.g., symmetry about the axes, symmetry about the origin, points of interse

Find out the probability, a)  A husband and wife appear in an interview for...

a)  A husband and wife appear in an interview for two vacancies in the same post.  The probability of husband's selection is 1/7 and that of wife's selection is 1/5.  What is th

Arthimetic progressions, what is the ratio of sides of a right angle triang...

what is the ratio of sides of a right angle triangle which are in A.P

Prove that a/b+c-a, a, b,c are in h.p prove that a/b+c-a, b/a+c-b, c/a+b-c ...

a, b,c are in h.p prove that a/b+c-a, b/a+c-b, c/a+b-c are in h.p To prove: (b+c-a)/a; (a+c-b)/b; (a+b-c)/c are in A.P or (b+c)/a; (a+c)/b; (a+b)/c are in A.P or 1/a; 1

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Q. Converting Mixed Numbers to Improper Fractions? Ans. Converting a mixed number to an improper fraction is easy. A single multiplication, and then a single addition:

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for what value of k,the following system of equations have infinite solutions?kx + 5y -(k-5)=0;20x +ky - k=0

Methods for doing integral, There are really three various methods for doin...

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