Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
QuestionWhat is key application of inverted siphons? What are major drawbacks of using inverted siphons?
AnswerInverted siphons are planned at locations in which sewer system is blocked by anti-establishment utilities, storm water drains. They are now and then known as depressed sewers as it is claimed that there is no real siphon action. They attach upstream and downstream sewers with U-shaped straight up alignment such that they forever running full. Drawbacks of inverted siphons are-(i) They induce extra head loss to sewer system which is disagreeable in hydraulic performance.(ii) U-shaped siphons construct sediment accumulation trouble and earlier experience showed that inverted siphons were simply blocked due to siltation; (iii) Protection of overturn siphons is complicated due to its isolation.
from surveying to school building finish
BRICKS Brick is obtained by moulding good clay into a block, which is dried and then burnt. It is the oldest building block to replace stone. Manufacture of brick started havin
Define Drag load test of shock transmission unit? This test ensures that excessive load should not be transmitted to the structure by the STU. As per the test the STU shall hav
derive equation of radial pressure and loop stresses of thick cylinder
fine the influence line for cantilever beam of span 7 m and load at 2 m?
Differences between epoxy grout, cement grout and cement mortar? Epoxy grout comprises epoxy resin, epoxy hardener and aggregates/sand.As a matter of fact, there are various ty
Q. Full bore flow in drainage design? In the design of gravity drainage pipes, full bore flow capacity is usually adopted to check against design runoff. Though one should note
Define the Thiem Equations for Confined Aquifers Using natural log: Q = 2pKm(h 2 - h 1 )/ln(r 2 /r 1 ) Using log 10 : Q = 2Km(h 2 - h 1 )/((1055)log(r 2 /r 1 ))
Determine the final stresses in the bolt: A steel bolt of diameter 12 mm and length 175 mm is used to clamp a brass sleeve of length 150 mm to a rigid base plate as in Figure.
what are the dimensions of a sheet of paper required for plotting a traverse ABCDE with 1 : 250 scale if a margin of 4 cm to the right and left sides and a6 cm margin to the other
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd