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Of course it is C[i] = A[i] + B[i].It was a typing mistake,never mind. You just understand the concept.
27-1 b.
for grain-size=1
n=A.length
grain-size=1
r=n
for k=0 to n-1
spawn ADD-SUBARRAY(A,B,C,k+1,min((k+1),n)
)
sync
This will make n sub branches all to be executed in parallel and finally sync instruction will cause the flow of execution to be synchronized at that point.
27-1 C.
x1 is the constant to represent computational cost of spawning a new process. This step is executed (n/grain-size) number of times. x2 is the constant to represent the computational cost of the addition operation. This step is executed (grain-size) number of times for each spawned preocess in parallel. Hence total time for a parallel thread is x1(n/grain-size) + x2.(grainsize)
planning the solution
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#include #include #include using namespace std; #define MAX 5 #define INF (1 #define DEBUG if(0) #define pii pair #define pb(x) push_back(x) class
Ask question #Mi fd d fffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff
limitation of function
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