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Of course it is C[i] = A[i] + B[i].It was a typing mistake,never mind. You just understand the concept.
27-1 b.
for grain-size=1
n=A.length
grain-size=1
r=n
for k=0 to n-1
spawn ADD-SUBARRAY(A,B,C,k+1,min((k+1),n)
)
sync
This will make n sub branches all to be executed in parallel and finally sync instruction will cause the flow of execution to be synchronized at that point.
27-1 C.
x1 is the constant to represent computational cost of spawning a new process. This step is executed (n/grain-size) number of times. x2 is the constant to represent the computational cost of the addition operation. This step is executed (grain-size) number of times for each spawned preocess in parallel. Hence total time for a parallel thread is x1(n/grain-size) + x2.(grainsize)
how to decode the numerals to string..
#question:-program to counts tha no of occurances of the string in the nth padovan string
how to write a c program for stone game
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A: no, can't. The names of, precedence of, associativity of, and arity of operators is fixed through the language. In C++, there is no operator** so you cannot create one for a
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