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Low level techniques (motion specific)
Techniques utilized to fully control the motion of any graphic object in any type of animation scene, these techniques are also considered as motion exact techniques since we can identify the motion of any graphic object in scene, techniques as interpolation, and approximation or so on, are utilized in motion specification of any of graphic object. Low level techniques are used when animator generally has a fairly specific idea of the precise motion as he or she needs.
Education training process falls into three general categories: 1) Instructor Support Products: These are used through teachers additionally to text books, lectures and other
(a) Differentiate between the following compression algorithm: 1. Shannon -Fano Algorithm and 2. Huffman Encoding (b) A statistical encoding algorithm is being considered
Raster and Random Scan Display Technologies For display or printing graphics objects, various technologies have been invented. Research and development is still on for getting
Advantages of JPEG Images Huge compression ratios mean sooner download speeds. JPEG produces outstanding results for main photographs and complicated images. JPEG s
QUESTION (a) People want to know design patterns. i) What should their attitude be about design patterns? ii) How can people use design patterns to do a better job?
Suppose P be the point object along with the coordinate (x,y,z). We want to translate such object point to the new position as, P'(x',y',z') through the translation Vector as V=t x
Traditional Animation techniques as: 1) Key Frames 2) Cel Animation Formula: Required Key frames for a film = {[Time(in seconds)]
What are the advantages of Bresenham's line drawing algorithm over DDA line drawing algorithm? DDA and Bresenham algorithms both are efficient line drawing algorithm. Breaenham
Essential Elements for the Raster Scan Display Three elements are essential for the raster scan display. They are as: 1) The Frame Buffer that is also termed as the Refresh
Acquire the perspective transformation onto z = - 2 Plane, where (0, 0, 18) is the center of projection. Solution: Now centre of projection, C (a, b, c) = (0, 0, 18) ∴ (n 1
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