Loops and subroutines, Electrical Engineering

Assignment Help:

1.....If viewing this through the Assignment tool, click the title above to go to the Submissions area.

Introduction

The purpose of this experiment is to examine the operation of loops and their close equivalent, subroutines.

Procedure

1. How many times does each loop execute?

2. Assemble and link to create LOOPS.EXE. Run the program.

3. Comment out the PUSH AX and POP AX instructions. Re-assemble, link, and run. Comment on any changes. Explain how the changes, if any, occurred.

4. Put the PUSH AX and POP AX instructions back in.

5. Take instructions from inside the loop and place them in a subroutine (or procedure). Thus, the loop will call the subroutine once each pass. Only instructions that directly control the looping should stay.

6. Assemble, link, and run the program. You should get the same results. Email the final ASM file.

7. Assemble and link to create LOOPS2.EXE. Run the program. Explain why the loop pass counter value shown is correct.

8. This file contains errors! Edit the file to correct the errors, then assemble, link, and run. Warning! The program may assemble and link correctly and still have errors that may crash your DOS window. The correct result in AL is 7.

9. Submit your findings.

Downloaded copy of Program LOOPS.ASM: Count the number of passes through a loop.

;

        .MODEL SMALL

        .DATA

LOOPS   DW    ?

MSG     DB    'The number of loop passes is '

TENTHOS DB    ?

THOUS   DB    ?

HUNS    DB    ?

TENS    DB    ?

ONES    DB    ?

        DB    0DH,0AH,'$'

 

        .CODE

        .STARTUP

        MOV   AX,0      ;clear loop pass counter

;

;place user loop code here.

;Make sure INC  AX is inside the innermost loop.

;

        MOV   BX,0FF98H

BAK:    PUSH  AX

        MOV   CX,1234H

        MOV   DX,5678H

        XOR   CX,DX

        MOV   AX,9ABCH

        XOR   CX,AX

        POP   AX

        INC   AX                ;increment loop pass counter

        DEC   BX

        JNZ   BAK

;

;end of user loop code

;

        MOV   LOOPS,AX          ;display the loop pass counter

        CALL  BTOD

        LEA   DX,MSG 

        MOV   AH,9

        INT   21H

        .EXIT

 

BTOD    PROC  FAR

        MOV   AX,LOOPS    ;load binary input value

        SUB   DX,DX

        MOV   BX,10000

        DIV   BX                ;get 10,000s digit

        ADD   AL,30H

        MOV   TENTHOS,AL

        XCHG  AX,DX

        SUB   DX,DX

        MOV   BX,1000           ;get 1,000s digit

        DIV   BX

        ADD   AL,30H

        MOV   THOUS,AL

        XCHG  DX,AX

        MOV   BL,100

        DIV   BL          ;get hundreds digit

        ADD   AL,30H      ;convert into ASCII digit

        MOV   HUNS,AL     ;and save

        XCHG  AL,AH       ;get remainder

        SUB   AH,AH       ;prepare for division by 10

        MOV   BL,10

        DIV   BL          ;get tens digit

        ADD   AL,30H      ;convert into ASCII digit

        MOV   TENS,AL     ;and save

        ADD   AH,30H      ;convert ones digit into ASCII

        MOV   ONES,AH     ;and save

        RET

BTOD    ENDP

        END


Related Discussions:- Loops and subroutines

Mixed bonding, Mixed Bonding Displayed by III-V compounds bonding p...

Mixed Bonding Displayed by III-V compounds bonding partly ionic and partly covalent. Ionic character of bonding becomes much more prominent since the constituent atoms m

Program description , Program Description In the above  program  any t...

Program Description In the above  program  any two  numbers can be stored in register A and B ( by  replacing XX  and YY). Contents  of B are  compared with A. If  B CY = 0

Minimized circuit using or and and not gate, Given S(F) = A'B +'C'D + C'D +...

Given S(F) = A'B +'C'D + C'D +'A'B + 'A B + 'A 'C + 'A D + 'A C A. DRAW A MINIMIZED CIRCUIT USING ONLY OR AND NOT GATES (2 input gates) B. WRITE THE WIRE LIST Example of a

Unit impulse response of a linear system, Q. The unit impulse response h(t)...

Q. The unit impulse response h(t) of a linear system is h(t) = 5e -t cos(2t - 30°). Determine H(s).

Ac link chopper - power supplies , AC Link Chopper This copper  has two...

AC Link Chopper This copper  has two  stage conversion. First DC is converted into AC  by the  use of inverter. The  magnitude of AC voltage is  varied  by the  transformer and

Motor., if load is removed so which motor will run fast? series or shunt?

if load is removed so which motor will run fast? series or shunt?

Determine the energy, Q. Consider a pair of coupled coils as shown in Figur...

Q. Consider a pair of coupled coils as shown in Figure of the text, with currents, voltages, and polarity dots as indicated. Show that the mutual inductance is L 12 = L 21 = M by

Input bias current of operational amplifier, Q. Input bias current of opera...

Q. Input bias current of operational amplifier? When operated at extremely low quiescent current values, the base bias currents will be low; but they do have to be taken into c

Dc simulation component, Once you are happy with the biasing components you...

Once you are happy with the biasing components you will need to disable the DC simulation component and enable the SP component. (Right click the component and then select the "com

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd