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1. For the ER diagram you created in assignment, the artefact of the conceptual database design, map the ER model into the relational model according to how it was designed in the ER diagram. You may however first refine your ER diagram if necessary. The actual assessment of this part is in the point below.
2. For all the relations that arise from this ("first-cut") ER diagram, list all those that are already in 3NF. If there are some relations that are not in 3NF yet, then convert them into 3NF with proper procedure and explanations.
3. Draw the global relation diagram for your final, revised, and normalised database design, and keep all the relevant details there. It should be in a similar form to Figure of the textbook, but all the attributes should be kept there too. Include in the diagram all the primary keys, foreign keys, and the multiplicity constraints. Identify and discuss the potential data redundancies or anomalies that may still exist in your design, if any.
Polynomials like 5x 4 + 2x 3 + 7x 2 + 10x - 8 can be represented by using arrays. Arithmetic operations such as addition & multiplication of polynomials are com
Draw a flowchart of a Booth''s multiplication algorithm and explain it.
Q. By giving an example show how multidimensional array can be represented in one the dimensional array.
What are the Dynamic arrays Dynamic arrays are convenient for programmers since they can never be too small-whenever more space is needed in a dynamic array, it can simply be e
Q. Make a BST for the given sequence of numbers. 45,32,90,34,68,72,15,24,30,66,11,50,10 Traverse the BST formed in Pre- order, Inorder and Postorder.
Q. Write down the algorithm to insert an element to a max-heap which is represented sequentially. Ans: The algorithm to insert an element "newkey" to
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bfs and dfs
/* The program accepts matrix like input & prints the 3-tuple representation of it*/ #include void main() { int a[5][5],rows,columns,i,j; printf("enter the order of
Ans: A procedure to reverse the singly linked list: reverse(struct node **st) { struct node *p, *q, *r; p = *st; q = NULL; while(p != NULL) { r =q;
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