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y2/3(y4/3\y1/3
4(3x-2) -5(x+1)=6-(4x-3)
I don''t understand
Assume that P ( x ) is a polynomial along with degree n. Thus we know that the polynomial have to look like, P ( x ) =ax n
3 with exponent of x-2=7
how do I write 4x^3-62 in descending order
I have an algebra test tomorrow and still don''t understand how to simplify and solve radicals
Find g(f(h(-3))). f(x) = 2x -- g(x) = -3x+4 -- h(x) = -2x-8
what is the definition of e
if the roots of a quadratic equation are (-2+sqrt 6) and (-2-sqrt 6), what is the equation in ax^2+bx+c=0 form?
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