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Solve for x: 4 log x = log (15 x2 + 16)
Solution: x4 - 15 x2 - 16 = 0
(x2 + 1)(x2 - 16) = 0
x = ± 4
But log x is not described when x = - 4, the x = 4 is the only answer.
How do you reflect about the origin
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limit 0 to 2(3x^2+2) Solution) integrate 3x^2 to x^3 and 2 to 2x and apply the limit from 0 to 2 answer is 12.
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Any point on parabola, (k 2 ,k) Perpendicular distance formula: D=(k-k 2 -1)/2 1/2 Differentiating and putting =0 1-2k=0 k=1/2 Therefore the point is (1/4, 1/2) D=3/(32 1/2
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