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Solve for x: 4 log x = log (15 x2 + 16)
Solution: x4 - 15 x2 - 16 = 0
(x2 + 1)(x2 - 16) = 0
x = ± 4
But log x is not described when x = - 4, the x = 4 is the only answer.
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Taking 2^x=m and solving the quadratic for getting D>=0 we get range= [3/4 , infinity )
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