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Solve for x: 4 log x = log (15 x2 + 16)
Solution: x4 - 15 x2 - 16 = 0
(x2 + 1)(x2 - 16) = 0
x = ± 4
But log x is not described when x = - 4, the x = 4 is the only answer.
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Above we have seen that (2x 2 - x + 3) and (3x 3 + x 2 - 2x - 5) are the factors of 6x 5 - x 4 + 4x 3 - 5x 2 - x - 15. In this case we are able to find one facto
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