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Solve for x: 4 log x = log (15 x2 + 16)
Solution: x4 - 15 x2 - 16 = 0
(x2 + 1)(x2 - 16) = 0
x = ± 4
But log x is not described when x = - 4, the x = 4 is the only answer.
how to find the minimum distance between any two particles which are in relative motion?
Can anyone help with my exam. I have 8 questions to do which is due on 02-14-13
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