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Linear Approximations
In this section we will look at an application not of derivatives but of the tangent line to a function. Certainly, to get the tangent line we do have to take derivatives, thus in some way this is an application of derivatives as well.
Given a function, f ( x ) , we can determine its tangent at x = a . The equation of the tangent line, that we'll call L ( x ) for this discussion, is,
L ( x ) = f ( a ) + f ′ ( a ) ( x - a )
Take a look at the given graph of a function & its tangent line.
From the graph we can illustrates that near x = a the tangent line & the function have closely the similar graph. On instance we will utilizes the tangent line, L ( x ) , as an approximation to the function, f ( x ) , near x = a . In these cases we call the tangent line the linear approximation to the function at x = a .
A rectangular field is to be fenced in completely. The width is given as 22 yd and the total area is 990 yd 2 . Determine the length of the field? a. 31 yd b. 45 yd c. 968
Differentiate following. f ( x ) = sin (3x 2 + x ) Solution It looks as the outside function is the sine & the inside function is 3x 2 +x. The derivative is then.
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Proof of: lim q →0 (cos q -1) / q = 0 We will begin by doing the following, lim q →0 (cosq -1)/q = lim q →0 ((cosq - 1)(cosq + 1))/(q (cosq + 1)) = lim q
2.46825141458*1456814314.446825558556
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Explain Measurement Conversions in details? The following tables show measurements of length, distance, and weight converted from one system to the other. Length and Distanc
a sketch of two dimensional system
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Need Solution Find (dy)/( dx) for; (i). y = x 7 (ii). y = x 2γ (iii). y = x -3 (iv). y = x
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