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Sketch Line Segment That Joining By Using Bresenham Line Algorithm
Example: Sketch line segment that joining (20, 10) and (25, 14) by using Bresenham line generation algorithm.
Solution: (x0, y0) → (20, 10) ; (x1, y1) → (25, 14)
m = (y1- y0)/(x1 - x0)
= (14- 10)/(25 - 20)
= 4/5 < 1
Like, m = (Δy)/ (Δx)
= 4/5 =› Δy = 4
→ plot point (20, 10)
pi = 2Δy - Δx
i = 1: pi = 2 * 4 - 5 = 3
Here p1 > 0 consequently x0 ← 21; y0 ← 11 now plot (21, 11)
i = 2 as p1 > 0
∴p2 = p1 + 2(Δy - Δx)
= 3 + 2 (4 - 5) = 3 - 2 = 1
p2 > 0; hence x0 ← 22; y0 ← 12 plot (22,12)
i = 3 as p2 > 0
∴p3 = p2 + 2 (Δy - Δx) = 1 + 2 (4 - 5) = - 1
p3 < 0 ∴x0 ← 23
y0 ← 12
plot (23, 12)
i = 4 as p3 < 0
∴p4 = p3 + 2Δy
= -1 + 2 * 4 = 7
∴ x0 ← 24; y0 ← 13
plot (24, 13)
i = 5 as p4 > 0
∴p5 = p4 + 2 (Δy - Δx)
= 7 + 2 (4 - 5) = 5
x0 ← 25; y0 ← 14
Plot (25, 14)
{for i = 6, x0 will be > xi so algorithm terminates
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