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limit x-a/|x-a| equals x-a [a]a [b]0 [c]-a [d]none 0f these
am i going to get As
Let Consider R A Χ B, S B Χ C be two relations. Then compositions of the relations S and R given by SoR A Χ C and is explained by (a, c) €(S o R) iff € b € B like (a, b) € R,
Proof of Alternating Series Test With no loss of generality we can assume that the series begins at n =1. If not we could change the proof below to meet the new starting place
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how to prove Decidability Theorem of Logic
if the limit is x tends to zero then there are two conditions 1) if a ia +ve the answer is -1 2) if a is -ve the answer is +1 if x tends to a the answer is +1 only so the answer is [d]
if the limit is x tends to zero then there are two conditions
1) if a ia +ve the answer is -1
2) if a is -ve the answer is +1
if x tends to a the answer is +1 only
so the answer is [d]
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