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limit x-a/|x-a| equals x-a [a]a [b]0 [c]-a [d]none 0f these
what is 8x6 is
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Consider x € R. Then the magnitude of x is known as it's absolute value and in general, shown by |x| and is explained as Since the symbol always shows the nonnegative
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Prove: 1/cos2A+sin2A/cos2A=sinA+cosA/cosA-sinA
Inverse Sine : Let's begin with inverse sine. Following is the definition of the inverse sine. y = sin -1 x ⇔ sin y = x for - ?/2 ≤ y ≤ ?/2 Hen
Definite Integral : Given a function f ( x ) which is continuous on the interval [a,b] we divide the interval in n subintervals of equivalent width, Δx , and from each interval se
Find the solution to the subsequent IVP. ty' - 2y = t 5 sin(2t) - t 3 + 4t 4 , y (π) = 3/2 π 4 Solution : First, divide by t to find the differential equation in the accu
if the limit is x tends to zero then there are two conditions 1) if a ia +ve the answer is -1 2) if a is -ve the answer is +1 if x tends to a the answer is +1 only so the answer is [d]
if the limit is x tends to zero then there are two conditions
1) if a ia +ve the answer is -1
2) if a is -ve the answer is +1
if x tends to a the answer is +1 only
so the answer is [d]
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