Limit comparison test - sequences and series, Mathematics

Assignment Help:

Limit Comparison Test

Assume that we have two series ∑an and ∑bn with an, bn  ≥ 0 for all n. Determine,

444_Limit Comparison Test 1.png

If c is positive (i.e. c > 0 ) and is finite (i.e. c < ∞ ) afterwards either both series converge or both of the series diverge.

Notice that it doesn't actually matter which series term is in the numerator for this test, we could just have easily illustrated c as,

1309_Limit Comparison Test 2.png

and we would get similar results. To observe why this is, consider the subsequent two definitions.

131_Limit Comparison Test 3.png

Initiate with the first definition and rewrite it as follows, afterwards take the limit.

1240_Limit Comparison Test 4.png

Alternatively, if ?c is positive and finite then so is c‾ and if c‾ is positive and finite then so is c.  Similarly if c‾ = 0 then c = ∞ and if c‾ = ∞ then c = 0. Both of the above definitions will give similar results from the test so don't worry as regards which series terms should be in the numerator and that should be in the denominator.  Select this to make the limit easy to calculate.

As well, this really is a comparison test in some other ways.  If c is positive and finite this is saying that both of the series terms will behave in usually the same way and thus we can expect the series themselves to as well behave in an identical fashion.  If c = 0 or c = ∞ we can't say this and thus the test fails to provide any information. 

The limit in this test will frequently be written like this:

2394_Limit Comparison Test 5.png

as frequently both terms will be fractions and this will build the limit easier to deal with.


Related Discussions:- Limit comparison test - sequences and series

Binary to decimal, 01010011 01100101 01101101 01110000 01100101 01110010 00...

01010011 01100101 01101101 01110000 01100101 01110010 00100000 01000110 01101001 00100001

Arithmetico geometric progression, find the sum of the following series upt...

find the sum of the following series upto n terms: 1*2+2*4+3*8+4*16+.....

Area problem, Area Problem Now It is time to start second kind of inte...

Area Problem Now It is time to start second kind of integral: Definite Integrals.  The area problem is to definite integrals what tangent & rate of change problems are to d

Finds out the center and radius of circle, Finds out the center & radius of...

Finds out the center & radius of each of the following circles & sketch the graph of the circle. a) x 2 + y 2 = 1 b) x 2 + ( y - 3) 2  = 4 Solution In all of these

Area of an ellipse, You know the experation for the area of a circle of rad...

You know the experation for the area of a circle of radius R. It is Pi*R 2 . But what about the formula for the area of an ellipse of semi-minor axis of length A and semi-major

Arthemetic progreession, ball are arranged in rows to form an equilateral t...

ball are arranged in rows to form an equilateral triangle .the firs row consists of one abll,the second of two balls,and so on.If 669 more balls are added,then all the balls canbe

Illustration of rank correlation coefficient, Illustration of Rank Correlat...

Illustration of Rank Correlation Coefficient In a beauty competition two assessors were asked to rank the 10 contestants by using the professional assessment skills. The resul

Demerits and merit-the geometric mean , The geometric mean Merits ...

The geometric mean Merits i.  This makes use of all the values described except while x = 0 or negative ii.   This is the best measure for industrial increase rates

Find out the roots of the subsequent pure quadratic equation, Find out the ...

Find out the roots of the subsequent pure quadratic equation: Find out the roots of the subsequent pure quadratic equation. 4x 2 - 100 = 0 Solution: Using Equation

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd