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Left-handed limit
We say
provided we can make f(x) as close to L as we desire for all x sufficiently close to a and x Note that the change in notation is extremely minor and actually might be missed if you aren't paying attention. The only difference is the bit i.e. under the "lim" part of the limit. For the right- handed limit now we have x → a- (note the "+") which means that we know will only look at x>a. Similarly for the left-handed limit we have x → a- (note the "-") that means that we will only be looking at x Let's now take a look at the some problems and look at one-sided limits rather than the normal limit.
Note that the change in notation is extremely minor and actually might be missed if you aren't paying attention. The only difference is the bit i.e. under the "lim" part of the limit. For the right- handed limit now we have x → a- (note the "+") which means that we know will only look at x>a. Similarly for the left-handed limit we have x → a- (note the "-") that means that we will only be looking at x Let's now take a look at the some problems and look at one-sided limits rather than the normal limit.
Let's now take a look at the some problems and look at one-sided limits rather than the normal limit.
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ABC is a right triangle right-angled at C and AC=√3 BC. Prove that ∠ABC=60 o . Ans: Tan B = AC/BC Tan B = √3 BC/BC Tan B =√3 ⇒ Tan B = Tan 60 ⇒ B = 60
statement of gauss thm
Write down the equation of the line which passes through the points (2, -1, 3) and (1, 4, -3). Write all three forms of the equation of the line. Solution To do the above
a²+b²=1 a+b
34+8-76=
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