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Horizontal tangents for parametric equations, Horizontal tangents for Param...

Horizontal tangents for Parametric Equations Horizontal tangents will take place where the derivative is zero and meaning of this is that we'll get horizontal tangent at value

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Chain Rule :   If f(x) and g(x) are both differentiable functions and we describe F(x) = (f. g)(x) so the derivative of F(x) is F′(x) = f ′(g(x)) g′(x).  Proof We will s

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A pole has to be erected at a point on the boundary of a circular park of diameter 13m in such a way that the differences of its distances from two diametrically opposite fixed gat

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Exponential Functions : We'll begin by looking at the exponential function,                                                              f ( x ) = a x We desire to differe

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Integration, ((1/x^1/2-(x-1)^1/2)+(1/(5-3(x-1)^2)^1/2)

((1/x^1/2-(x-1)^1/2)+(1/(5-3(x-1)^2)^1/2)

Algebra, Evaluate: 30 - 12÷3×2 =

Evaluate: 30 - 12÷3×2 =

Ratio, how can i solve it

how can i solve it

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