Leak repair torquing procedure, Mechanical Engineering

Assignment Help:

Q. Leak Repair Torquing Procedure?

Attempt to tighten only the bolts contained within an arc that includes the leak area plus one or two bolts either side of the leak to the original torque values. A criss-cross torquing sequence should be used. If the leak does not stop, repeat the torquing procedure using increments of 50 ft-lbs. (68 N-m) up to the maximum over torquing value.

If the bolts cannot be tightened, the stud bolts contained in the arc of the leak shall be removed one at a time and cleaned or replaced if damaged. Lubricate the bolts and reinstall. Torque the bolts to the full torque value. Follow the same torquing sequence as above. Repeat the sequence using increments of 50 ft-lbs. (68 N-m) up to the maximum over torquing value.

If no results are achieved, go to the bolt on the flange directly opposite to the center of the leak, loosen it and retighten it to its proper torque. Ten, working one bolt at a time on opposite sides of the first bolt, readjust all the bolts on the side of the flange opposite the leak. It may be necessary to repeat this operation to get even bolt loading. When this operation is complete, go back to the bolt in the center of the leak and retighten as outlined above.

If these procedures are still not successful in stopping the leak, consider using hot/cold setting compounds with special enclosures or taking the piping system out of service for permanent repair.


Related Discussions:- Leak repair torquing procedure

Nature of bending stress, According to the explanation, why reverse will ha...

According to the explanation, why reverse will happen in the case of cantilevers? ( that is, tensile stresses will be induced in upper layers and compressive stresses will be induc

Steps for solving problem for finding maximum power, Step s for Solving Pr...

Step s for Solving Problem for Finding Maximum Power: 1. Use formula stress (σ) = force (Maximum Tension)/Area Where;  Area = b.t that is, T max = σ.b.t 2. Unit mass (

Find out bulk modulus, Find out bulk modulus: A steel bar of 25 mm dia...

Find out bulk modulus: A steel bar of 25 mm diameter was tested on a gauge length of 250 cm in tension and in torsion. A tensile load of 50 kN generated an extension of 0.13 m

CUPOLA FURNACE, With the help of neat diagrams explain various parts of Cup...

With the help of neat diagrams explain various parts of Cupola. Define its operation. How the thermal efficiency of Cupola calculated?

Draw shear force and bending moment diagrams, A cantilever of length 2m car...

A cantilever of length 2m carries a uniformly distributed load of 1.5 KN/m run over the whole length and appoint load of 2KN at a distance of 0.5 from the free end draw the Shear

Capacity planning, Capacity Planning: This unit defined different ways...

Capacity Planning: This unit defined different ways to measure capacity, set up maximum capacity, and calculate capacity utilization. The long-term and short-term strategies t

Motorcycle pulls to one side motorcycle problem, If Motorcycle Pulls to One...

If Motorcycle Pulls to One Side Causes of Problem Remedy Misaligned shock Absorber Front and rear wheels are not alig

Example of equilibrium - mechanics, Example of Equilibrium: Express i...

Example of Equilibrium: Express in terms of θ, β and W the force T necessary to hold weight in equilibrium as shown in the figure given below. Also derive an expression f

Alloys, hardenability of ferrous and non ferrous alloys

hardenability of ferrous and non ferrous alloys

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd