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LDS/LES Instruction execution :
LAHF: Load AH from Lower Byte of Flag: - This instruction loads the AH register with the lower byte of the flag register. This instruction can be utilized to observe the status of all the condition code flags (except over flow) at a time.
SAHF: Store AH to Lower Byte of Flag Register. This instruction resets or sets the condition code flags (except overflow) in the lower byte of the flag register depending on the equivalent bit positions in AH. If a bit in AH is value1, the flag equivalent to the bit position is set, else it is reset.
PUSHF: Push Flags to Stack: - The push flag instruction pushes the flag register on the stack; first the upper byte and then the lower byte will be pushed on the stack. The SP is decremented by value 2, for each push operation. The basic operation of this instruction is same to the PUSH operation.
POPF: Pop Flags from Stack:-The pop flags instruction loads the flag register totally (both bytes) from the word contents of the memory location currently addressed by SS and SP. The SP is incremented by the value 2 for each pop operation.
Register Organization of 8086 8086 has a great set of registers containing special purpose and general purpose registers. All the 8086 resisters are 16-bit registers.
how we can multiply two 8 bit number with rotation
Example : Write a program to move the contents of the memory location 0500H to BX and also to register CX. Add immediate byte 05H to the data residing in memory location, whose ad
Ask question #MinimuWHAT ARE CONSTANTS AND WHAT DO THEY DO?m 100 words accepted#
IInd Generation Microprocessor : The second generation microprocessor by using n MOS technology seemed in the market in 1973. The Intel 8080, of nMOS technology
8086 Minimum mode System and Timing In a minimum mode 8086 system, the microprocessor 8086 is operated in minimum mode by strapping its MN/MX pin to logic 1.All the control si
8254 Programmable Timer A diagram of Intel's 8254 interval event/timer counter is given in Figure. The 8254 consists of 3 identical counting circuits, per of which has GATE and
You have to write a subroutine (assembly language code using NASM) for the following equation.
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