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LDS/LES Instruction execution :
LAHF: Load AH from Lower Byte of Flag: - This instruction loads the AH register with the lower byte of the flag register. This instruction can be utilized to observe the status of all the condition code flags (except over flow) at a time.
SAHF: Store AH to Lower Byte of Flag Register. This instruction resets or sets the condition code flags (except overflow) in the lower byte of the flag register depending on the equivalent bit positions in AH. If a bit in AH is value1, the flag equivalent to the bit position is set, else it is reset.
PUSHF: Push Flags to Stack: - The push flag instruction pushes the flag register on the stack; first the upper byte and then the lower byte will be pushed on the stack. The SP is decremented by value 2, for each push operation. The basic operation of this instruction is same to the PUSH operation.
POPF: Pop Flags from Stack:-The pop flags instruction loads the flag register totally (both bytes) from the word contents of the memory location currently addressed by SS and SP. The SP is incremented by the value 2 for each pop operation.
General Data Registers Given figure indicate the register organization of 8086. The registers DX, CX, BX and AX are the general purpose 16-bit registers. AX is behaved as 16-bi
Pin diagram of 8088 : The pin diagram of 8088 is shown in given figure. Most of the 8088 pins and their functions are exactly similar to the corresponding pins of 8086. Hence
Part A: Bitwise Logical and Shift Operations Create a SPARC assembly language program that extracts a bit-field from the contents of register %l0. The position of the rightmos
Machine Level Programs In this section, a few machine levels programming instance, rather then, instruction sequences are presented for comparing the 8086 programming with that
8088 Timing System Diagram The 8088 address/data bus is divided in 3 parts (a) the lower 8 address/data bits, (b) the middle 8 address bits, and (c) the upper 4 status/
Write an assembly language program that will: accept keyboard input of a positive integer value N; compute the sum S= 1+ 2 + 3 + ... + N; print (output) the computed su
program to accept 23 students name using while loop let your variable control the value negative 4
ASSUME: Assume Logical Segment Name:- The ASSUME directive which is used to inform the assembler, the specified names of the logical segments to be consider for different segme
#write a program 8086 to find the largest number
ali is impressed_____ ahmed''s grades.
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