Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Ladder friction:
.: A ladder is an arrangement which is used for climbing on the walls. It consists of two long uprights of wood or iron and connected by many cross bars. These cross bars are called as rungs and provide steps for climbing. The figure given below shows a ladder AB with its end A resting on ground and end B leaning against the wall. The ladder is acted upon by following set of forces:
(1) Weight W acting downwards at the midpoint of it.
(2) Normal reaction Rh and friction force Fh = µRh at end B leaning against wall. As the ladder has a tendency to slip downwards, friction force will be acting upwards. If the wall is smooth (µ = 0), friction force will be zero.
(3) Normal reaction Ra and friction force Fa =µRa at end A resting on floor. As the ladder, upon slipping, tends to move away from wall, the direction of friction force will be towards wall.
By applying equilibrium conditions, the algebraic sum of horizontal component and vertical component of forces would be zero.
How we say that motion of the follower is simple harmonic motion describe in practical approch
Conventional Priority Rules The standard solution for production scheduling (routing and sequencing) difficulties is the utilization of priority rules. A priority rule is an o
what are the advanteges of the working ?
SURFACE MODELING: The process of modeling is built much easier for a mathematical description of an object or at least on a part of the object might be applied. Surfaces might
Normal 0 false false false EN-IN X-NONE X-NONE MicrosoftInternetExplorer4
Given these sinusoids: x1(t) = 0.5cos(25t+20 o ), x2(t)=0.85cos(25t+160 o ) and x3(t)= 0.81cos(25t-145 o ) (a) Subplot the phasors X1, X2 and X3 corresponding to the thee si
uses of parallelogram
the component of computer integrated manufacturing with the diagram
Evaluate the point of contraflexure: An overhanging beam of 15 m span is carrying a consistently distributed load of 1 kN/m over the length of 10 m at a distance 5 m from the
Draw bending moment diagram for the beam: A cantilever beam carries a uniformly distributed load of 2 t/m over the total length of 6 m and point loads of 5 t, 3 t, 7 t & 2 t a
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd