Kruskals algorithm, Data Structure & Algorithms

Assignment Help:

Krushkal's algorithm uses the concept of forest of trees. At first the forest contains n single node trees (and no edges). At each of the step, we add on one (the cheapest one) edge so that it links two trees together. If it makes a cycle, simply it would mean that it links two nodes that were connected already. So, we reject it.

The steps in Kruskal's Algorithm are as:

1.   The forest is constructed through the graph G - along each node as a separate tree in the forest.

2.   The edges are placed within a priority queue.

3.   Do till we have added n-1 edges to the graph,

  I.   Extract the lowest cost edge from the queue.

 II.   If it makes a cycle, then a link already exists among the concerned nodes. So reject it.

 III.  Otherwise add it to the forest. Adding it to the forest will join two trees together.

The forest of trees is a division of the original set of nodes. At first all the trees have exactly one node in them. As the algorithm progresses, we make a union of two of the trees (sub-sets), until the partition has only one sub-set containing all the nodes eventually.

Let us see the sequence of operations to determine the Minimum Cost Spanning Tree(MST) in a graph via Kruskal's algorithm. Suppose the graph of graph shown in figure  and below figure  illustrates the construction of MST of graph of Figure

1339_Kruskals Algorithm.png

Figure: A Graph

Figure: Construction of Minimum Cost Spanning Tree for the Graph by application of Kruskal's algorithm

The following are several steps in the construction of MST for the graph of Figure via Kruskal's algorithm.

Step 1 :  The lowest cost edge is chosen from the graph that is not in MST (initially MST is empty). The cheapest edge is 3 that is added to the MST (illustrated in bold edges)

Step 2: The next cheap edge which is not in MST is added (edge with cost 4).

Step 3 : The next lowest cost edge that is not in MST is added (edge with cost 6).

 Step 4 : The next lowest cost edge that is not in MST is added (edge with cost 7).

Step 5 : The next lowest cost edge that is not in MST is 8 but form a cycle. Hence, it is discarded. The next lowest cost edge 9 is added. Now the MST has all the vertices of the graph. This results in the MST of the original graph.


Related Discussions:- Kruskals algorithm

Addressing modes, Compare zero-address, one-address, two-address, and three...

Compare zero-address, one-address, two-address, and three-address machines by writing programs to compute: Y = (A – B X C) / (D + E X F) for each of the four machines. The inst

Last in first out method, This method is the reverse of FIFO and assumes th...

This method is the reverse of FIFO and assumes that each issue of stock is made from latest items received in the enterprises .Thus if the last lot to be received is not sufficient

Minimum cost spanning trees, A spanning tree of any graph is only a subgrap...

A spanning tree of any graph is only a subgraph that keeps all the vertices and is a tree (having no cycle). A graph might have many spanning trees. Figure: A Graph

How many nodes in a tree have no ancestor, How many nodes in a tree have no...

How many nodes in a tree have no ancestors 1 node in atree have no ancestors.

Discuss the brute force algorithm, Question 1 What do you mean by Amortiza...

Question 1 What do you mean by Amortization? Question 2 Explain the following Big Oh notation (O) Omega notation (Ω) Theta notation (Θ)   Question 3 Di

Define the term - array, Define the term - Array A fixed length, ord...

Define the term - Array A fixed length, ordered collection of values of same type stored in contiguous memory locations; collection may be ordered in several dimensions.

Define minimum spanning tree, Define Minimum Spanning Tree A minimum sp...

Define Minimum Spanning Tree A minimum spanning tree of a weighted linked graph is its spanning tree of the smallest weight, where the weight of a tree is explained as the sum

Multiple queue, #questionalgorithm for implementing multiple\e queues in a ...

#questionalgorithm for implementing multiple\e queues in a single dimensional array

Comparisions and assignments in worst case, Q. Calculate that how many key ...

Q. Calculate that how many key comparisons and assignments an insertion sort makes in its worst case?        Ans: The worst case performance occurs in insertion

Red black tree, red black tree construction for 4,5,6,7,8,9

red black tree construction for 4,5,6,7,8,9

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd