Kolmogorov-smirnov - normal probability plot, Applied Statistics

Assignment Help:

The Null Hypothesis - H0:  The random errors will be normally distributed

The Alternative Hypothesis - H1:  The random errors are not normally distributed

Reject H0: when P-value ≤ α = 0.05

109_Normal Probability Plots2.png

As the P value is 0.043 it is less than the 0.05 significance level therefore reject H0 and accept H1 as there is sufficient evidence to show that random errors are not normally distributed.  The assumption of normality is possibly satisfied as the normal probability plot is close to the straight line.


Related Discussions:- Kolmogorov-smirnov - normal probability plot

Linear programming problem, Melissa Bakery is preparing for the coming than...

Melissa Bakery is preparing for the coming thanksgiving festival. The bakery plans to bake and sell its favourite cookies; butter cookies, chocolate cookies and almond cookies. A k

Critique 2, prepare a critical analysis of a quantitative study focusing on...

prepare a critical analysis of a quantitative study focusing on protection of human participants data collection data management and analysis problem statement and interpretation o

Type i and ii errors, TYPE I AND II Errors If a statistical hypothesis ...

TYPE I AND II Errors If a statistical hypothesis is tested, we may get the following four possible cases: The null hypothesis is true and it is accepted; The

Scatter diagram - correlation analysis, Scatter Diagram The first step ...

Scatter Diagram The first step in correlation analysis is to visualize the relationship. For each unit of observation in correlation analysis there is a pair of numerical value

Evaluate the standard deviation, You have an assembly line which produces 1...

You have an assembly line which produces 1L bottles of seltzer with a standard deviation of 0.05L. • Assuming the distribution of volume is normal, what is the chance any single

#title., 1 Se toma una muestra de 81 observaciones con una desviación están...

1 Se toma una muestra de 81 observaciones con una desviación estándar de 5. La media de la muestra es de 40. Determine el intervalo de de confianza de 99% para la media

Difference between correlation and regression analysis, Difference between ...

Difference between Correlation and Regression Analysis 1. Degree and Nature  of Relationship: Coefficient of correlation measures   the degree  of covariance  between two vari

Penman-monteith method, (a) Average rainfall during the month of January...

(a) Average rainfall during the month of January is found to be 58 mm. A Class A pan evaporation recorded an average of 8.12 mm/day near an irrigation reservoir. The average

Kurtosis and skew, how to interpret results, a good explanation to help me ...

how to interpret results, a good explanation to help me understand.

PERCENTAGES, CALCULATE THE PERCENTAGE OF REFUNDS EXPECTED TO EXCEED $1000 U...

CALCULATE THE PERCENTAGE OF REFUNDS EXPECTED TO EXCEED $1000 UNDER THE CURRENT WITHHOLDING GUIDELINES

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd