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Q. How does the distinction among kernel mode and user mode function as a rudimentary form of protection (security) system?
Answer: The distinction among kernel mode and user mode provides a rudimentary form of protection in the following manner. Certain instructions could be executed merely when the CPU is in kernel mode. Likewise hardware devices could be accessed only when the program is executing in kernel mode. Control over when disrupt could be enabled or disabled is also possible only when the CPU is in kernel mode. Therefore the CPU has very limited capability when executing in user mode thereby enforcing protection of critical resources.
What are batch systems? Batch systems are quite appropriate for implementing large jobs that need little interaction. The user can submit jobs and return later for the results.
A page fault causes the following sequence to occur. 1. Trap (shut in) to the operating system. 2. Save the process registers and process state. 3. Verify that the interr
How does user specify block to be fetched in direct access? By specifying the relative block number, relative to first block in file, which is block 0.
List sample file types, based on use, on the VAX under VMS. source programs (.BAS, .FOR, .COB, .PLI, .PAS, .MAR) data files (.DAT) text files (.TXT) command proced
Define Instance. An instance is an administrative unit in which components of R/3 systems giving one or more services are grouped together. The services offered by a case are
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What is paging? Name the different paging techniques. Paging is a memory management method that permits the physical-address space of a process to be noncontiguous. Paging evad
The code should be nicely formatted with plenty of comments. It should be easy to read, properly The summary section should include three parts: (1) Record the running t
Write a short note on disk scheduling One of the responsibities of operating system O/S is to use the hardware efficiently. Whenever a process requires I/O to or from the
What is internal fragmentation? Consider holes of 20k assume the process requests 18 bites. If we allocate accurately the request block, we are left with a hole of 2k. The over
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