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IRET : Return from ISR:-
When an interrupt service routine is called, before transferring control to it, the IP, CS register and flag registers are stored in the stack to mention the location from where the execution is to be continued, after the ISR is executed. Hence, in the ending of each ISR, when IRET is executed, the values of IP, CS register and flags are retrieved from the stack to continue the execution of the main program. The stack is modified consequently.
LOOP : Loop Unconditionally:-
This instruction executes the part of the program from the address or label mention in the instruction up to the loop instruction, CX number of times. Following sequence describe the execution. On every iteration, register CX is decremented automatically. In other terms, this instruction implements JUMF IF NOT ZERO and DECREMENT COUNTER structure.
The execution proceeds in the sequence, after the loop is executed, CX number of times. Lf CX is already OOH, the execution continues in sequence. Flags are remaining unaffected by this instruction.
Displacement addressing technique
INC: Increment : - This instruction increments the contents of the particular memory or register location by the value 1. All the condition code flags are affected except the carry
define accounting.briefly explain the accounting concepts which guide the accountant at the recording stage.
#write a program 8086 to find the largest number
You are to write an assembly language program called subfaq.s that computes the generalized subfactorial function of nonnegative integer inputs i0 and n. The generalized subfactori
LENGTH : Byte Length of a Label: This directive is not available in MASM. This is used to mention to the length of a data array or a string. MOV CX. LENGTH ARRAY This sta
Task One Produce a menu such as the one below (remember to keep to this specification). M E N U 1, Enter Number 1 2, Enter Number 2 3, Display num1 and num2 4, D
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
Open notepad and enter the code for a program that calculates the following arithmetic expression: x = a + b + c - d - e + f The operands a, b, c, d, e, f, and x should be declared
Part A: Bitwise Logical and Shift Operations Create a SPARC assembly language program that extracts a bit-field from the contents of register %l0. The position of the rightmos
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