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IRET : Return from ISR:-
When an interrupt service routine is called, before transferring control to it, the IP, CS register and flag registers are stored in the stack to mention the location from where the execution is to be continued, after the ISR is executed. Hence, in the ending of each ISR, when IRET is executed, the values of IP, CS register and flags are retrieved from the stack to continue the execution of the main program. The stack is modified consequently.
LOOP : Loop Unconditionally:-
This instruction executes the part of the program from the address or label mention in the instruction up to the loop instruction, CX number of times. Following sequence describe the execution. On every iteration, register CX is decremented automatically. In other terms, this instruction implements JUMF IF NOT ZERO and DECREMENT COUNTER structure.
The execution proceeds in the sequence, after the loop is executed, CX number of times. Lf CX is already OOH, the execution continues in sequence. Flags are remaining unaffected by this instruction.
I can get it to copy the string but can''t get it to reverse it.
When Seen in the choir, Terry was the picture of an angelic devil. I have to underline the predicate twice
Intel's 8237 DMA controller : 1) The 8237 contain 4 independent I/O channels 2) It contains 27 registers, 7 of which are system-wide registers and 5 for each channel. 3)
Read Architecture: Look Through Main memory that located is conflicting the system interface. The least concerning feature of this cache unit is that it remain between the proc
this is my first project i dont know where to start
The problem to be solved and implemented with an ARM assembly language program You are asked to do some image processing on an image composed of characters shaped in For exa
add the contents of the defined memory locations 120, 133, 122 using mov instruction in dosbox
wap proram for bthe addition of two 3*3 matrix
The modes are determined by the contents of the control register, whose format is given in Figure These modes are: Mode 0: If a group is in mode 0, it is divided into 2 sets.
As an instance of the normal priority mode, imagine that initially AEOI is equal to 0 and all the ISR and IMR bits are clear. Also consider that, as shown in given figure, requests
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