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IRET : Return from ISR:-
When an interrupt service routine is called, before transferring control to it, the IP, CS register and flag registers are stored in the stack to mention the location from where the execution is to be continued, after the ISR is executed. Hence, in the ending of each ISR, when IRET is executed, the values of IP, CS register and flags are retrieved from the stack to continue the execution of the main program. The stack is modified consequently.
LOOP : Loop Unconditionally:-
This instruction executes the part of the program from the address or label mention in the instruction up to the loop instruction, CX number of times. Following sequence describe the execution. On every iteration, register CX is decremented automatically. In other terms, this instruction implements JUMF IF NOT ZERO and DECREMENT COUNTER structure.
The execution proceeds in the sequence, after the loop is executed, CX number of times. Lf CX is already OOH, the execution continues in sequence. Flags are remaining unaffected by this instruction.
write and run a programme using 8086 assembly language that interchange the lower four bits of AL registered with upper four bits.
Architecture Of 8088 The register set of 8088 is accurately the same as in to 8086. The architecture of 8088 is also same to 8086 except for 2 changes; a) 8088 has 4-byte instr
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Write an assembly program that will compute and output tuition cost: a. accept keyboard input of the number of credit hours taken b. accept keyboard input of the type of classes 1
SHR : Shift Logical Right: This instruction performs bit-wise right shifts on the operand word or byte that might be reside in a memory location or a register, by the specified c
Assembly Code for Reading Flow & Generating Serial Output The timer is timer 1 is set for the baud rate 9600, as the crystal used is of 11.0592 Hz. Then the timer 1 is starte
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Modes of 8254 : Mode 0 (Interrupt on Terminal Count)-GATE which value is 1 enables counting and GATE which value is 0 disables counting, and GATE put not effect on
how we can multiply two 8 bit number with rotation
Write an 8086 program to find out the number of positive numbers and negative numbers from a given series of signed numbers include flow chart ..
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