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This unit introduces the topic of evaluating interactive products. It is a short unit as evaluation is discussed in more detail in Block 4. Its brevity should give you additional time to work on your TMA. Evaluation checks that users can use the product and like it. Evaluation assesses how well, or otherwise, the usability goals and user experience goals for an interactive product have been satisfied in a particular design. Evaluation is one of the key activities in the ID lifecycle and as such is central to M364. You should not think that because evaluation is not taught in detail until the final block of the module that it is unimportant. Without evaluation you can never know whether the ID process has been successful, so it is essential, and in reality you will probably need to keep evaluating throughout the process.In particular, the unit discusses some of the basic principles of evaluation - referred to as the 'why, what, where and when' of evaluation. It then describes three approaches to evaluation: usability testing; field studies; and analytical evaluations, explaining how these can be combined and how sometimes it is appropriate to apply these in an opportunistic manner. This discussion is complemented by an introductory video programme which introduces the topic of evaluation.
2. Write a program to separate out positive and negative numbers from a given series of 16-bit hexadecimal numbers.
.MODEL SMALL .STACK 100H .DATA PROMPT DB \''The 256 ASCII Characters are : $\'' .CODE MAIN PROC MOV AX, @DATA ; initialize DS MOV DS, AX
a program that display English letters excluding vowels
write a programme the addition two 3*3 matrix and stored in from list
8088 Timing System Diagram The 8088 address/data bus is divided in 3 parts (a) the lower 8 address/data bits, (b) the middle 8 address bits, and (c) the upper 4 status/
Write a program to evaluate the following expression. You are to evaluate the following equation: num1 - (input + num2) - (num3 + num4) Input will be a hex number input by
SEG : Segment of a Label:- The SEG operator is which is used to decide the segment address of the, variable, label or procedure and substitutes the segment base address in plac
NOT : Logical Invert: The NOT instruction complements (inverts) the contents of an a memory location or operand register bit by bit. The instance are as following: Example :
what is implied addressing
SHR : Shift Logical Right: This instruction performs bit-wise right shifts on the operand word or byte that might be reside in a memory location or a register, by the specified c
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