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INTO : Interrupt on Overflow:-
It is executed, when the overflow flag OF is set. The new contents of IP and CS register are taken from the address 0000:0000 as described in INT type instruction. It is equal to a Type 4 interrupt instruction.
JMP : Unconditional lump:-
This instruction transfers the control unconditionally of execution to the specified address by using an 8-bit or 16-bit displacement (intra segment relative, long or short) or CS : IP (intersegment direct far). Flags are not affected by this instruction. Corresponding to the three technique of specifying jump addresses, the JUMP instruction has following formats.
Using the AddSub program from Ch3 under c:\Masm615\examples as a reference, write a program that subtracts three 16-bit integers using only registers. Insert a call DumpRegs statem
2. Write a program to separate out positive and negative numbers from a given series of 16-bit hexadecimal numbers.
Interrupt System Based on Single 8259 A The 8259A is contained in a 28-pin dual-in-line package that need only a + 5-V supply voltage. Its organization is shown in given figur
SEG : Segment of a Label:- The SEG operator is which is used to decide the segment address of the, variable, label or procedure and substitutes the segment base address in plac
how to store a bulk data in a external eeprom
Using the windows32 framework, write a complete 80x86 program for Programming Exercises 4.3 number 3, on pages 130-131 of the textbook. Follow all coding conventions mentioned in
a- Trace the following program fragment and find out the content of ax after the the execution of the program. X db 5,7 -3,-9,4,-7,9 Mov
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
Basic Microprocessor Architecture and Interface : Introduction: Intel launches its first 4-bit microprocessor 4004 in the year 1971 and 8-bit microprocessor 8008 in the y
TEST : Logical Compare Instruction: The TEST instruction performs bit by bit logical AND operation on the 2 operands. Each bit of the result is then set to value I, if the equival
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