Interrupt table-how interrupt table processed-microprocessor, Assembly Language

Assignment Help:

Interrupt Table

Each interrupt level has a booked memory location, called an interrupt vector.  All these vectors (or pointers) are stored in the interrupt table. Table lies at linear address zero, or with 64KB segments, at 0000:0000. Every vector is two words long (4 bytes). The high word has the offset and the low word the segment of the INT handler.

How INT's are Processed :

Since there are 256 levels and each vector is 4bytes long so the table contains 1024 bytes (256*4=1024). The INT number is multiplied by four to fetch the address from the table.               

Whenever the CPU registers an INT it will push the FLAGS register to the stack and also push the IP and CS registers.  After that the CPU deactivates the interrupt system.  Then it acquires the 8-bit value the interrupting device sends and multiplies this by four to acquire the offset in the interrupt table. From this offset it acquires the address of the INT handler and carries over execution to this handler.

Usually the handler enables the interrupt system immediately to let interrupts with higher priority. Some devices also require a signal that the interrupt has been acknowledged. When the handler is stop (terminated) it might signal the 8259A PIC with an EOI (End of Interrupt). Then handler executes an IRET instruction.

 


Related Discussions:- Interrupt table-how interrupt table processed-microprocessor

Cbw-cwd-arithmetic instruction-microprocessor, CBW: Convert Signed Byte to...

CBW: Convert Signed Byte to Word: This instruction converts a signed byte to a signed word. In other terms, it copies the sign bit of a byte to be converted to all of the bits in

Right triangle, code, Assembly Language How to print strings in Right Tria...

code, Assembly Language How to print strings in Right Triangle form?

Introduction to 80 x 86 assembly language, Using the windows32 framework, w...

Using the windows32 framework, write a complete 80x86 program for Programming Exercises 4.3 number 3, on pages 130-131 of the textbook. Follow all coding conventions mentioned in

Interrupt system based on 8259 a-microprocessor, Interrupt System Based on ...

Interrupt System Based on Single 8259 A The 8259A is contained in a 28-pin dual-in-line package that need only a + 5-V supply voltage.  Its organization is shown in given figur

Dec-micro processor, DEC : A powerful new Alpha 64 bit RISC computer ch...

DEC : A powerful new Alpha 64 bit RISC computer chip was introduced in the year 1977, as new VAX (Virtual Address Extension) Computer. The VAX was 32 bit computer line based on

Nible, calculate the number of one bits in bx and complement an equal numbe...

calculate the number of one bits in bx and complement an equal number of least significant bits in ax hint use the xor instruction

Segment registers-microprocessor, Segment Registers The 8086 addresses ...

Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea

Project, Any small project which can implement on any software. No need any...

Any small project which can implement on any software. No need any external hardware approach.

Quarters, There are two parts to this assignment. The first part has you r...

There are two parts to this assignment. The first part has you reading 4 integers representing; #QUARTERS, #DIMES, #NICKELS & #PENNIES, respectively. Your program should compute t

Computer organization, write a program using assembly language that print y...

write a program using assembly language that print your name

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd