Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Interrupt Table
Each interrupt level has a booked memory location, called an interrupt vector. All these vectors (or pointers) are stored in the interrupt table. Table lies at linear address zero, or with 64KB segments, at 0000:0000. Every vector is two words long (4 bytes). The high word has the offset and the low word the segment of the INT handler.
How INT's are Processed :
Since there are 256 levels and each vector is 4bytes long so the table contains 1024 bytes (256*4=1024). The INT number is multiplied by four to fetch the address from the table.
Whenever the CPU registers an INT it will push the FLAGS register to the stack and also push the IP and CS registers. After that the CPU deactivates the interrupt system. Then it acquires the 8-bit value the interrupting device sends and multiplies this by four to acquire the offset in the interrupt table. From this offset it acquires the address of the INT handler and carries over execution to this handler.
Usually the handler enables the interrupt system immediately to let interrupts with higher priority. Some devices also require a signal that the interrupt has been acknowledged. When the handler is stop (terminated) it might signal the 8259A PIC with an EOI (End of Interrupt). Then handler executes an IRET instruction.
Memory Segmentation : The memory in an 8086/8088 based system is organized as segmented memory. In this scheme, the whole physically available memory can be divided into a n
Format of Control Register The format for the control register is given in Figure. Bit 0 of this register might be one before data may be output and bit two might be one
Interrupt Table Each interrupt level has a booked memory location, called an interrupt vector. All these vectors (or pointers) are stored in the interrupt table. Table lies at
A/D conversion: Basic tasks: (a) Write a program that will read and display the analog voltage on pin PE7 approximately once every second. (b) Write a program that will read and d
Read Architecture : Look Aside Cache In "look aside" cache architecture the main memory is located conflictingthe system interface. Both the cache main memory sees a bus cycle
CISC Characteristics : The design of an instruction set for a computer might take into consideration not only machine language constraints, but also the requirements i
Write an Lc-3 assembly language program to read in a sequence of single-digit positive integers from the keyboard(one integer per line) until the sentinel value of 0 is reached and
The modes are determined by the contents of the control register, whose format is given in Figure These modes are: Mode 0: If a group is in mode 0, it is divided into 2 sets.
describes vertical and horizontal web services protocols. Next, identify the similarities and differences between vertical and horizontal web services protocols. Finally, explain w
segmentation and overlapping in assemble language
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd