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Describe a interface 'Human' with methods as walk' and 'speak'. Describe a class 'User' implementing 'Human'. Describe a work() method in User class.Add a class 'Person' also executing Human. Add a method 'Behave' inPerson class. In Main method make objects of Person and User andassign them to 'Human' type and call Human methods. Can the work and Behave methods be called by Human types? Can we make the interface objects by calling interface Constructors ? Justify your answer.
Data logging This technique involves collecting data automatically using sensors; frequently used when doing scientific experiments or monitoring a system.
A set of techniques that allow executing a program which is not entirely in memory is called ? Ans. virtual memory which allows executing a program that is not entirely in me
What is layer? A layered system is ordered set of virtual worlds. Every build-in terms of one's below it and providing the execution basis for one above it. The objects in ever
ADDING LAYERS TO THE TIMELINE AND GIVING MOTION TO THE LAYER Step 1: Choose Layer from Common toolbar after that draw a layer. Step 2: Write the text inside Layer. Step
DRAM consists of MOSFET's but the technique is to use the drain source capacitance to hold charge. If charge is present logic '1' is held, no charge logic '0'. As you know capacito
Credit cards and smart cards Credit cards comprise a magnetic stripe on the back made up of iron-based particles in a plastic film. Stripe is split up into 3 tracks which a
what is batch system?how the disadvantage of batch system are overcome in multi-programming operating system?also describe how multi-programmed operating system is milestone in dev
3-variable K-maps have 8 squares which arenormally arranged in 4 columns and 2 rows.Columns are labeled with 2 variables. The columns are arranged so that either A or B cha
Question: a) Consider a car having a collision detection mechanism. Write an algorithm (in simple English) to illustrate the collision detection mechanism. b) The same car
What is verilog case (1) ? wire [3:0] x; always @(...) begin case (1'b1) x[0]: SOMETHING1; x[1]: SOMETHING2; x[2]: SOMETHING3; x[3]: SOMETHING4; endcase
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