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Q. Interconnection network in the form of a Linear Array?
The sorting problem particularly selected is bubble sort and interconnection network may be represented as n processors interconnected with one another in form of a linear array like displayed in Figure below. The method adopted for solving the bubble sort is called odd-even transposition. Suppose an input sequence is B= (b1, b2, b3, b4......... bn) and every number is assigned to a specific processor. In the odd-even transposition the sorting is done with the help of two stages known as odd phase and even phase. In the odd stage the elements stored in (p1, p2), (p3, p4), (p5, p6)......... (pn-1, pn) are compared according to Figure and consequently exchanged if needed it implies that if they are out of order. In even phase the elements stored in (p2, p3), (p4, p5), (p6, p7)......... (pn-2, pn-1) are compared according to the Figure and consequently exchanged if needed i.e. if they are out of order. Remember in the even phase the elements stored in p1 and pn aren't exchanged and compared. The total number of phases needed for sorting the numbers is n it implies that n/2 even phases and n/2 odd phases. The algorithmic demonstration of the above considered odd-even transposition is given below:
Figure: Interconnection network in the form of a Linear Array
1+3+5+....... +11
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