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Intel's 8237 DMA controller :
1) The 8237 contain 4 independent I/O channels
2) It contains 27 registers, 7 of which are system-wide registers and 5 for each channel.
3) Out of 5 register: 4 are 16-bit and 1 is 6-bit. they are
what is double hashing
8088 Timing System Diagram The 8088 address/data bus is divided in 3 parts (a) the lower 8 address/data bits, (b) the middle 8 address bits, and (c) the upper 4 status/
NEG: Negate:- The negate instruction forms the 2's complement of the particular destination in the instruction. For obtaining 2's complement, it subtracts the contents of destinat
Example : Write a program to move the contents of the memory location 0500H to BX and also to register CX. Add immediate byte 05H to the data residing in memory location, whose ad
The real time System (RTS) : Calling the clock real-time is somewhat of a misnomer because it only shows the time setting it has been given. The RTC is the other half of chip
(1) Write a program that will: (a) display "Enter Your Name:" (b) convert the entered name to Capital letters (if small), If any other character is entered, the program wil
General Data Registers Given figure indicate the register organization of 8086. The registers DX, CX, BX and AX are the general purpose 16-bit registers. AX is behaved as 16-bi
General Bus Operation The 8086 has a joined data and address bus commonly referred to as a time multiplexed address and data bus. The major reason behind multiplexing address
For an 8088 the 2 addresses linked with an 8259A are normally consecutive, and the AO line is associated to the AO pin, but because there are just 8 data pins on the 8259A and the
Write a MIPS/SPIM assembly language program that prints the smallest and largest values found in a non-empty table of N word-sized integers. The address of the first entry in your
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