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Intel's 8237 DMA controller :
1) The 8237 contain 4 independent I/O channels
2) It contains 27 registers, 7 of which are system-wide registers and 5 for each channel.
3) Out of 5 register: 4 are 16-bit and 1 is 6-bit. they are
Segment Registers The 8086 addresses a segmented memory unlike 8085. The complete 1 megabyte memory, which 8086 is capable to address is divided into 16 logical segments.Thusea
Convert 751 to hex and show what it would look like stored at TheNumber WORD ? (hint: answer in hex pairs)
Pin functions for the minimum mode operation of 8086 are following: 1) M/I/O -Memory/IO: This is a status line logically equivalent to S2 in maximum mode. When it is low, it
program to add two matrices
Cache components The cache sub-system may be divided into 3 functional blocks: Tag RAM, SRAM and theCache Controller. In real designs, these blocks can be implemented by multi
write a program to divide 2 numbers
Problems: 1. Write a single program. Each of the problems (2-4) should be written within a procedure. Your “main” procedure should call each procedure. Before calling each proc
String Manipulation Instruction A series of words or data bytes are available in memory at consecutive locations, to be mention to individually or collectively, are known as by
Assembler Directives and Operators The major advantage of machine language programming is directly that the memory control is in the hands of the programmer, so that, he can be
Format of Control Register The format for the control register is given in Figure. Bit 0 of this register might be one before data may be output and bit two might be one
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