Integration by parts, Mathematics

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? (2x+3)dx

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Y=Theea[sin(inTheeta)+cos(inTheeta)], Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷d...

Y=θ[SIN(INθ)+COS(INθ)],THEN FIND dy÷dθ. Solution)  Y=θ[SIN(INθ)+COS(INθ)] applying u.v rule then dy÷dθ={[ SIN(INθ)+COS(INθ) ] dθ÷dθ }+ {θ[ d÷dθ{SIN(INθ)+COS(INθ) ] }    => SI

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