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Integration
We have, so far, seen that differential calculus measures the rate of change of functions. Differentiation is the process of finding the derivative (rate of change) of a function F(x) and is denoted by F'(x) Often, we may know the rate of change, F'(x) of a function F(x) which is unknown to us. In such situations we would like to find out the original function F(x) from the derivative, F'(x). Reversing the process of differentiation and finding out the original function from the derivative is called integration. The original function, F(x) is called the integral.
The left hand side of the equation is read as "the indefinite integral of f(x) with respect to x. The symbol is the integral sign, f(x) is the integrand and 'c' is an arbitrary constant. The arbitrary constant 'c' is added because of the following reason:
If d/dx {F(x)} = f(x) then we can also write that d/dx {F(x) + c} = f(x) where 'c' is an arbitrary constant, because the derivative of any constant is zero.
The equation ax2 + 2hxy + by2 =0 represents a pair of straight lines passing through the origin and its angle is tan q = ±2root under h2-ab/(a+b) and even the eqn ax2+2hxy+by2+2gx+
Euler''s Constant (e) Approximate the number to the one hundredth, one ten-thousandths, and one one-hundred-millionth.
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Illustrates that the following numbers aren't solutions to the given equation or inequality. y = -2 in 3( y + 1) = 4 y - 5 Solution In this case in essence we do the sam
Adding Equally Sized Groups: Once children have had enough practice of making groups of equal size, you can ask them to add some of these equal groups. They can now begin to atte
Q. Find Common Denominators? What does it mean? Say you have two fractions, like 1/3 and 8/21 And they have different denominators (3 and 21). Sometimes, you'd prefer
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on 30 april, anthony purchased television invoiced at rm 6999 with cash discount terms of 2/10, 1/15, n/30 and also a trade discount 1.5%, 2%, 3.25%. In order to pay the invoice, h
Find out the volume of the solid obtained by rotating the region bounded by y = x 2 - 2x and y = x about the line y = 4 . Solution: Firstly let's get the bounding region & t
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