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How many integers satisfy the inequality |10(x+1)/x^2+2x+3|=1? Solution) first thing thats not an inequality,and second thing its very easy if thats the question.the LHS = |10/x^2 + 10/x + 2x + 3| = 110/x^2 will also be an integer only if x^2<10.....i.e. x<3.hence x= 0,+1,-1,+2,-2,+3,-3.but the only value that holds the equality is -1.hence the no. of INTEGERS is only 1.
Function of a Function Suppose y is a function of z, y = f(z) and z is a function of x, z = g(x)
WHAT IS PRECALC
2x+57=65 find x
#There is a balance of $1,234 and this person receive a refund check in the amount of $25 with her paycheck that was deposited into her account for $1500 which made her balance $27
Telescoping Series It's now time to look at the telescoping series. In this section we are going to look at a series that is termed a telescoping series. The name in this c
pythagoras theorem
a data set has a mean of 3, a median of4, and a mode of 5, which number must be in the data set 3,4,or5
Solve -10 cos(3t )= 7 on [-2,5]. Solution Let's first get the inverse cosine portion of this problem taken care of. cos(3 t )= - 7/10 ⇒ 3t = cos -1 ( - 7
Evaluate following sin 2 ?/3 and sin (-2 ?/3) Solution: The first evaluation in this part uses the angle 2 ?/3. It is not on our unit circle above, though notice that 2 ?/
?x7=54
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