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How many integers satisfy the inequality |10(x+1)/x^2+2x+3|=1? Solution) first thing thats not an inequality,and second thing its very easy if thats the question.the LHS = |10/x^2 + 10/x + 2x + 3| = 110/x^2 will also be an integer only if x^2<10.....i.e. x<3.hence x= 0,+1,-1,+2,-2,+3,-3.but the only value that holds the equality is -1.hence the no. of INTEGERS is only 1.
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how do i write a conjecture about the sum of two negative integers.
Consider the equation e x 3 + x 2 - x - 6 = 0, e > 0 (1) 1. Apply a naive regular perturbation of the form do derive a three-term approximation to the solutions
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