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How many integers satisfy the inequality |10(x+1)/x^2+2x+3|=1? Solution) first thing thats not an inequality,and second thing its very easy if thats the question.the LHS = |10/x^2 + 10/x + 2x + 3| = 110/x^2 will also be an integer only if x^2<10.....i.e. x<3.hence x= 0,+1,-1,+2,-2,+3,-3.but the only value that holds the equality is -1.hence the no. of INTEGERS is only 1.
Do All Our Activities Involve Mathematics? : The answer to this is 'yes' and 'no'. For those who look for mathematics and know where to look for it, it is 'yes'. For those who do
find the modulus Z=(2-i)(5+i12)/(1+i2)^3
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calculate x+2+y=4
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