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How many integers satisfy the inequality |10(x+1)/x^2+2x+3|=1? Solution) first thing thats not an inequality,and second thing its very easy if thats the question.the LHS = |10/x^2 + 10/x + 2x + 3| = 110/x^2 will also be an integer only if x^2<10.....i.e. x<3.hence x= 0,+1,-1,+2,-2,+3,-3.but the only value that holds the equality is -1.hence the no. of INTEGERS is only 1.
The Daily News reported that 54% of people surveyed said in which they would vote for Larry Salva for mayor. Based on the survey results, if 23,500 people vote in the election, how
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A business has the opportunity to expand by purchasing a machine at a cost of £80,000. The machine has an estimated life of 5 years and is projected to generate a cashflow of £20,0
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By pigeonhole principle, show that if any five numbers from 1 to 8 are chosen, then two of them will add upto 9. Answer: Let make four groups of two numbers from 1 to 8 like
Solve 6 sin ( x/2)= 1 on [-20,30] Solution Let's first work out calculator of the way since that isn't where the difference comes into play. sin( x/2)= 1/6 ⇒x/2= sin
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