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How many integers satisfy the inequality |10(x+1)/x^2+2x+3|=1? Solution) first thing thats not an inequality,and second thing its very easy if thats the question.the LHS = |10/x^2 + 10/x + 2x + 3| = 110/x^2 will also be an integer only if x^2<10.....i.e. x<3.hence x= 0,+1,-1,+2,-2,+3,-3.but the only value that holds the equality is -1.hence the no. of INTEGERS is only 1.
If $2,000 is invested in a savings account offering interest at a rate of 3.5% per year, compounded continuously, how fast is the balance growing after 8 years? (Round your answer
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Make a file called "testtan.dat" which has 2 lines, with 3 real numbers on every line (some negative, some positive, in the range from-1 to 3). The file can be formed from the edi
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Comparison Test Assume that we have two types of series ∑a n and ∑b n with a n , b n ≥ 0 for all n and a n ≤ b n for all n. Then, A. If ∑b n is convergent then t
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What is Identities and Contradictions ? Look at this equation: x + 1 = 1 + x It happens to be true always, no matter what the value of x. (Try it out! What if x is 43?)
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