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INT N : Interrupt Type N:-
In the interrupt structure of 8086/8088, 256 interrupts are distinct equivalent to the types from OOH to FFH. When an instruction INT N is executed, the TYPE byte N is multiplied by value 4 and the contents of IP and CS register of the interrupt service routine will be taken from hexadecimal multiplication (Nx4) as offset address and 0000 as the segment address. In other terms, the multiplication of type N by value 4 (offset) points to a memory block in the 0000 segment, which have the IP and CS register values of the interrupt service routine.
For the execution of this instruction, the IF ought to be enabled.
Example :
Therefore the instruction INT 20H will find out the address of the interrupt service routine as follows:
INT 20H
Type* 4 = 20 * 4 = 80H
Pointer to CS and IP of the ISR is 0000: 0080 H
Given figure shows the arrangement of CS and IP register addresses of the ISR in the interrupt vector table.
Assume that the registers are initialized to EAX=12345h,EBX =9528h ECX=1275h,EDX=3001h sub AH,AH sub DH,DH mov DL,AL mov CL,3 shl DX,CL shl AX,1 add DX,AX
OR: Logical OR: The OR instruction carries out the OR operation in the similar way as described in case of the AND operation. The restriction on source and destination operands ar
RCR: Rotate Right through Carry:- This instruction rotates the contents bit-wise of the destination operand right by the specified count through carry flag (CF). For each operati
64-bit integer calculator, which processes using 16-bits at a time (reg/mem16 operands)
BINARY TO GRAY CONVERSION
You have to write a subroutine (assembly language code using NASM) for the following equation.
Open notepad and enter the code for a program that calculates the following arithmetic expression: x = a + b + c - d - e + f The operands a, b, c, d, e, f, and x should be declared
Format of Control Register The format for the control register is given in Figure. Bit 0 of this register might be one before data may be output and bit two might be one
Will be needing help with assembly language assignments over the course of 4 weeks
program on basic calculator
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