Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
INT N : Interrupt Type N:-
In the interrupt structure of 8086/8088, 256 interrupts are distinct equivalent to the types from OOH to FFH. When an instruction INT N is executed, the TYPE byte N is multiplied by value 4 and the contents of IP and CS register of the interrupt service routine will be taken from hexadecimal multiplication (Nx4) as offset address and 0000 as the segment address. In other terms, the multiplication of type N by value 4 (offset) points to a memory block in the 0000 segment, which have the IP and CS register values of the interrupt service routine.
For the execution of this instruction, the IF ought to be enabled.
Example :
Therefore the instruction INT 20H will find out the address of the interrupt service routine as follows:
INT 20H
Type* 4 = 20 * 4 = 80H
Pointer to CS and IP of the ISR is 0000: 0080 H
Given figure shows the arrangement of CS and IP register addresses of the ISR in the interrupt vector table.
Explain the architecture of the file transfer protocol ftp in terms of clients, servers, sockets
Pin diagram of 8088 : The pin diagram of 8088 is shown in given figure. Most of the 8088 pins and their functions are exactly similar to the corresponding pins of 8086. Hence
AAD stand for what??
Flowchart for the sequence of 8251 Whether the control, mode or sync character register is selected depends on the accessing sequence. A flowchart of the sequencing is given i
code, Assembly Language How to print strings in Right Triangle form?
Cache controller The cache controller is the mind of the cache. Its responsibilities include: performing the snarfs and snoops, updating the TRAM and SRAM and implementing
RICS/CISC Architecture An essential aspect of computer architecture is the design of the instruction set for the processor. The instruction set selected for a specific compute
Ask 2. Exchange higher byte of AX and higher byte of BX registers by using memory location 0160 in between the transfer. Then stores AX and BX registers onto memory location 0174 o
END : END of Program:- The END directive marks the ending of the assembly language program. When the assembler comes across this END directive, it avoided the source lines avai
i have a question.
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd