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INT N : Interrupt Type N:-
In the interrupt structure of 8086/8088, 256 interrupts are distinct equivalent to the types from OOH to FFH. When an instruction INT N is executed, the TYPE byte N is multiplied by value 4 and the contents of IP and CS register of the interrupt service routine will be taken from hexadecimal multiplication (Nx4) as offset address and 0000 as the segment address. In other terms, the multiplication of type N by value 4 (offset) points to a memory block in the 0000 segment, which have the IP and CS register values of the interrupt service routine.
For the execution of this instruction, the IF ought to be enabled.
Example :
Therefore the instruction INT 20H will find out the address of the interrupt service routine as follows:
INT 20H
Type* 4 = 20 * 4 = 80H
Pointer to CS and IP of the ISR is 0000: 0080 H
Given figure shows the arrangement of CS and IP register addresses of the ISR in the interrupt vector table.
Write a program to solve problem 9, Summation Program, on page 179 of chapter 5 in the textbook (book:kip Irvine Assembly Language sixth edition)
PTR : Pointer:- The pointer operator which is used to declare the type of a variable, label or memory operand. The operator PTR is prefixed by either WORD or BYTE. If the prefi
IRET : Return from ISR:- When an interrupt service routine is called, before transferring control to it, the IP, CS register and flag registers are stored in the stack to ment
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http://www.raritanval.edu/uploadedFiles/faculty/cs/full-time/Brower/CISY256/2013Spring/CISY256%20Assembly%20Project.pdf
ORG : Origin:- The ORG directive directs the assembler to begin the memory allotment for the specific segment, code or block from the declared address in the ORG statement. W
INTO : Interrupt on Overflow:- It is executed, when the overflow flag OF is set. The new contents of IP and CS register are taken from the address 0000:0000 as described in INT
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