Instruction formats-microprocessor, Assembly Language

Assignment Help:

Instruction Formats

A machine language instruction format has 1 or more number of fields linked with it. The first field is known as operation code field or op code field, which show the type of the operation to be performed by the CPU. The instruction format also has other fields known as operand fields. The CPU executes the instruction by using the information which reside in these fields.

There are 6 general formats of instructions in 8086 instruction set. The length of an instruction can vary from one byte to six bytes. The instruction formats are given as following:

1) One byte Instruction:  This format is just one byte long and can have theregister operands or  implied data . The least significant 3-bits of the op code are referring for specifying the register operand, if any. Or else all the 8-bits form an opcode and the operands are implied.

2) Register  to Register: This format is 2 bytes long. The first byte of the code indicatethe operation code and width of the operand indicated by w bit. The second byte of the code indicate the register operands and R/M field, as given below.

2261_instruction1.jpg

The register represented  by the REG field is 1 of the operands.  The R/M field indicate  another register or memory location, for example. the other operand.

3) Register to/from Memory with no Displacement:  This format is 2 bytes long and same as the register to register format except for the MOD field as shown.

460_instruction2.jpg

The MOD field indicates the mode of addressing. The R/M, MOD,REG and the W fields are decided inTable 3.2.

4) Register  to/from  Memory  with Displacement:  This type of instruction  format have  one or two extra bytes for displacement along with 2-byte the format of the register to/from memory without displacement. The format is given.

2109_instruction3.jpg

5) Immediate Operand to Register: In this format, the first byte and the 3-bits from the second byte which are utilized for REG field in case of register to register format are utilized for opcode. It also has one or two bytes of immediate data. The complete instruction format is as given below.

360_instruction4.jpg

6) Immediate Operand to Memory with 16-bit Displacement:  This type of instruction format requires 5 or 6 bytes for coding. The first 2 bytes have the information regardingMOD, OPCODE and R/M fields. The remaining 4 bytes have 2 bytes of displacement and 2 bytes of data as shown.

 

2472_instruction5.jpg


Related Discussions:- Instruction formats-microprocessor

Interrupt system based on 8259 a-microprocessor, Interrupt System Based on ...

Interrupt System Based on Single 8259 A The 8259A is contained in a 28-pin dual-in-line package that need only a + 5-V supply voltage.  Its organization is shown in given figur

Operating System, Why is the capability to relocate processes desirable?

Why is the capability to relocate processes desirable?

Implemented with an arm assembly language program, The problem to be solved...

The problem to be solved and implemented with an ARM assembly language program You are asked to do some image processing on an image composed of characters shaped in For exa

Project ideas, can u please give me ideas on Assembly Language Projects usi...

can u please give me ideas on Assembly Language Projects using Nasm

Write policy-microprocessor, Write Policy A write policy determines how...

Write Policy A write policy determines how the cache deals with a write cycle. The 2 common write policies areWrite-Throughand Write-Back. In Write-Back policy, the cache behav

Nible, calculate the number of one bits in bx and complement an equal numbe...

calculate the number of one bits in bx and complement an equal number of least significant bits in ax hint use the xor instruction

Program for dispaying lcd characters, #include"lcd.asm"       ; assembly fi...

#include"lcd.asm"       ; assembly file is included for displaying lcd characters Main: PORTA EQU 0xF80  ; PORTS PORTB EQU 0xF81 PORTC EQU 0xF82 PORTD EQU 0xF83 R

Program to find the largest number in an array, Write a MC68H12 assembly la...

Write a MC68H12 assembly language program to find the largest number in an array of ten 8-bit numbers. The array is stored in memory locations starting at address $1100. Use branch

General data registers-microprocessor, General Data Registers Given fig...

General Data Registers Given figure indicate the register organization of 8086. The registers DX, CX, BX and AX are the general purpose 16-bit registers. AX is behaved as 16-bi

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd