Instruction formats-microprocessor, Assembly Language

Assignment Help:

Instruction Formats

A machine language instruction format has 1 or more number of fields linked with it. The first field is known as operation code field or op code field, which show the type of the operation to be performed by the CPU. The instruction format also has other fields known as operand fields. The CPU executes the instruction by using the information which reside in these fields.

There are 6 general formats of instructions in 8086 instruction set. The length of an instruction can vary from one byte to six bytes. The instruction formats are given as following:

1) One byte Instruction:  This format is just one byte long and can have theregister operands or  implied data . The least significant 3-bits of the op code are referring for specifying the register operand, if any. Or else all the 8-bits form an opcode and the operands are implied.

2) Register  to Register: This format is 2 bytes long. The first byte of the code indicatethe operation code and width of the operand indicated by w bit. The second byte of the code indicate the register operands and R/M field, as given below.

2261_instruction1.jpg

The register represented  by the REG field is 1 of the operands.  The R/M field indicate  another register or memory location, for example. the other operand.

3) Register to/from Memory with no Displacement:  This format is 2 bytes long and same as the register to register format except for the MOD field as shown.

460_instruction2.jpg

The MOD field indicates the mode of addressing. The R/M, MOD,REG and the W fields are decided inTable 3.2.

4) Register  to/from  Memory  with Displacement:  This type of instruction  format have  one or two extra bytes for displacement along with 2-byte the format of the register to/from memory without displacement. The format is given.

2109_instruction3.jpg

5) Immediate Operand to Register: In this format, the first byte and the 3-bits from the second byte which are utilized for REG field in case of register to register format are utilized for opcode. It also has one or two bytes of immediate data. The complete instruction format is as given below.

360_instruction4.jpg

6) Immediate Operand to Memory with 16-bit Displacement:  This type of instruction format requires 5 or 6 bytes for coding. The first 2 bytes have the information regardingMOD, OPCODE and R/M fields. The remaining 4 bytes have 2 bytes of displacement and 2 bytes of data as shown.

 

2472_instruction5.jpg


Related Discussions:- Instruction formats-microprocessor

Program translation sequence, Program Translation Sequence Developing ...

Program Translation Sequence Developing a software program to accomplish a particular task, the implementer chooses an appropriate language, develops the algorithm (a sequence

Assembly language programming, Write an assembly language program that defi...

Write an assembly language program that defines symbolic constants for all seven days of the week

Physical memory mapped and port input output-microprocessor, Physical Memor...

Physical Memory Mapped I/O and Port I/O : CPU controlled I/O comes in 2 ways. Simply the difference is whether we utilize the normal memory addresses for I/O, this is mention

Encrypting, write an assembly language program that has two subroutines : o...

write an assembly language program that has two subroutines : one for encrypting alphabates of a string and second fo decrypting the encoded string . in encryption simply converta

Add-arithmetic instruction-microprocessor, ADD:  Add :- This instruction ...

ADD:  Add :- This instruction adds an immediate contents of a memory location specified in the a register ( source ) or instruction to the contents of another register (destinat

Base convertor, take an integer and its base and the base in which you want...

take an integer and its base and the base in which you want to convert the number from user and perform conversion.

Shr-sar-logical instruction-microprocessor, SHR : Shift Logical Right: Thi...

SHR : Shift Logical Right: This instruction performs bit-wise right shifts on the operand word or byte that might be reside in  a memory location or a register, by the specified c

Space don''t come in ASCII characters while printing?, .MODEL SMALL .STACK...

.MODEL SMALL .STACK 100H .DATA PROMPT DB \''The 256 ASCII Characters are : $\'' .CODE MAIN PROC MOV AX, @DATA ; initialize DS MOV DS, AX

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd