Instruction formats-microprocessor, Assembly Language

Assignment Help:

Instruction Formats

A machine language instruction format has 1 or more number of fields linked with it. The first field is known as operation code field or op code field, which show the type of the operation to be performed by the CPU. The instruction format also has other fields known as operand fields. The CPU executes the instruction by using the information which reside in these fields.

There are 6 general formats of instructions in 8086 instruction set. The length of an instruction can vary from one byte to six bytes. The instruction formats are given as following:

1) One byte Instruction:  This format is just one byte long and can have theregister operands or  implied data . The least significant 3-bits of the op code are referring for specifying the register operand, if any. Or else all the 8-bits form an opcode and the operands are implied.

2) Register  to Register: This format is 2 bytes long. The first byte of the code indicatethe operation code and width of the operand indicated by w bit. The second byte of the code indicate the register operands and R/M field, as given below.

2261_instruction1.jpg

The register represented  by the REG field is 1 of the operands.  The R/M field indicate  another register or memory location, for example. the other operand.

3) Register to/from Memory with no Displacement:  This format is 2 bytes long and same as the register to register format except for the MOD field as shown.

460_instruction2.jpg

The MOD field indicates the mode of addressing. The R/M, MOD,REG and the W fields are decided inTable 3.2.

4) Register  to/from  Memory  with Displacement:  This type of instruction  format have  one or two extra bytes for displacement along with 2-byte the format of the register to/from memory without displacement. The format is given.

2109_instruction3.jpg

5) Immediate Operand to Register: In this format, the first byte and the 3-bits from the second byte which are utilized for REG field in case of register to register format are utilized for opcode. It also has one or two bytes of immediate data. The complete instruction format is as given below.

360_instruction4.jpg

6) Immediate Operand to Memory with 16-bit Displacement:  This type of instruction format requires 5 or 6 bytes for coding. The first 2 bytes have the information regardingMOD, OPCODE and R/M fields. The remaining 4 bytes have 2 bytes of displacement and 2 bytes of data as shown.

 

2472_instruction5.jpg


Related Discussions:- Instruction formats-microprocessor

Operating System, Why is the capability to relocate processes desirable?

Why is the capability to relocate processes desirable?

Dec-micro processor, DEC : A powerful new Alpha 64 bit RISC computer ch...

DEC : A powerful new Alpha 64 bit RISC computer chip was introduced in the year 1977, as new VAX (Virtual Address Extension) Computer. The VAX was 32 bit computer line based on

Program to add 8-bit series numbers-assembly language, Program: Write a pr...

Program: Write a program to perform addition of a series of 8-bit numbers. The series have 100 (numbers). Solution : In the first program, we have been implemented the add

Test-logical instruction-microprocessor, TEST : Logical Compare Instructio...

TEST : Logical Compare Instruction: The TEST instruction performs bit by bit logical AND operation on the 2 operands. Each bit of the result is then set to value I, if the equival

Compute the fibonacci sequence - assembly program, Compute the Fibonacci se...

Compute the Fibonacci sequence - assembly program: Problem: Fibonacci   In this problem you will write a program that will compute the first 20 numbers in the Fibonacci sequ

Assembly language programs-microprocessor, Assembly Language Example Progra...

Assembly Language Example Programs We studied the entire instruction set of 8086/88, pseudo-ops and assembler directives. We have explained the process of entering an assembly

Encrypting, write an assembly language program that has two subroutines : o...

write an assembly language program that has two subroutines : one for encrypting alphabates of a string and second fo decrypting the encoded string . in encryption simply converta

Declare a constant in assembly language, Declare 1 constant. This can be do...

Declare 1 constant. This can be done just below the prototype section. Put the following divider above the constant section. ;************************ Constants ****************

8086 assembly language program, move a byte string ,16 bytes long from the ...

move a byte string ,16 bytes long from the offset 0200H to 0300H in the segment 7000H

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd