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To delete an element in the list at the end, we can delete it without any difficult. But, assume if we desire to delete the element at the straining or middle of the list, then, we ought to rewrite all the elements after the position where the element that ought to be deleted exists. We ought to shift (r+1)th element to rthposition , where 'r' refer for position of deleted element in the list, the (r + 2)th element to (r + 1)th position, and it will continue till the (n)th element to ( n-1 )th position, where n refer to the number of elements in the list, and after that the count is decremented.
From the above instance, if we desire to delete an element '44' from the list. We ought to shift 55 to the 4th position, 66 to the 5th position, and 77 to the 6th position.
Before deletion
Count 1 2 3 4 5 6 7
11
22
33
44
55
66
77
Step 1
Step 2
Step 3
Count 1 2 3 4 5 6
merge sort process for an example array {38, 27, 43, 3, 9, 82, 10}. If we take a closer look at the diagram, we can see that the array is recursively divided in two halves till the
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null(nil) = true // nil refer for empty tree null(fork(e, T, T'))= false // e : element , T and T are two sub tree leaf(fork(e, nil, nil)) = true leaf(
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