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Find the length of the second diagonal of a rhombus, whose side is 5cm and one of the diagonals is 6cm.
Determine an actual explicit solution to y′ = t/y; y(2) = -1. Solution : We already identify by the previous illustration that an implicit solution to this IVP is y 2 = t 2 -
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performs the mentioned operation and write the answers in standard form. ( -4 + 7 i ) + (5 -10 i ) Solution Actually there isn't much to do here other than add or subt
3 1/2 x 1 4/7 x 1 1/3
how to compute the frequncy polygon of the scores?
Speaking Mathematically : A Class 2 teacher was explaining the concept of place value to his students, using the number eleven. He started by saying "One and one make eleven." So
If y 1 (t) and y 2 (t) are two solutions to y′′ + p (t ) y′ + q (t ) y = 0 So the Wronskian of the two solutions is, W(y 1 ,y 2 )(t) = =
For every girl taking classes at the martial arts school there are 3 boys who are taking classes at the school. If there are 236 students taking classes write and solve a proportio
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