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Improving GIF Compression: Features of LZW compression can be used to enhance its efficiency and thereby decrease the size of your graphic interchange format graphics. The strategy is to decrease the number of colours in your graphic interchange format image to the minimum number essential and to remove stray colours which are not required to present the image. A graphic interchange format graphic cannot have more than 256 colors although it can have fewer colours, down to a minimum of two as black and white. Images along with fewer colours will compress more efficiently in LZW compression.
Transformation for 3-D Rotation Rotation in 3-dimensions is considerably more complicated then rotation in 2-dimensions. In 2-Dimentional, a rotation is prescribed via an angl
Question 1: (a) Explain what are Final Gathering and Global Illumination and state why you would use those features when you render in MAYA. (b) List clearly the steps in
General Perspective transformation with COP at the origin Here we suppose the given point P(x,y,z) be projected like P'(x',y',z') on the plane of projection. The center of pro
Approaches to Area Filling Some other approaches to area filling are Scan line polygon fill algorithm Boundary fill algorithm Flood fill algorithm.
Q. Write a short note on area subdivision method for hidden surface removal. Ans. Area Subdivision This technique for hidden- surface removal is essentially an image- spac
DESCRIBE PHONG INTERPOLATION SHADING METHOD
Performing rotation about an Axis For performing rotation about an axis parallel to one of the coordinate axes (say z-axis), you first need to translate the axis (and hence the
A color histogram is a representation of the distribution of colors in an image. For digital images, a color histogram represents the number of pixels that have colors in each of a
Consider at line segment AB in the Figure k, parallel to the z-axis along with end points A (3, 2, 4) and B (3, 2, 8). Perform a perspective projection on the z = 0 plane from the
To prove: P (u = 0) = p0 Solution : = p 0 B n,0 (u) + p 1 B n, 1 (u) +...... + p n B n, n (u)...............(1) B n,i (u) = n c i u i (1 - u) n-i B n,0
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