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Implement the following function using 8 to 1 multiplexerY(A, B, C, D) = ∑(0,1,2,5,9,11,13,15)
Ans. We will obtain three variables B,C and D at selection lines and also A as input. Here eight inputs are given and they can be 0,1, A or A' depending upon the Boolean function.
I0
I1
I2
I3
I4
I5
I6
I7
A'
0 1 2 3 4 5 6 7
8 9 10 11 12 13 14 15
A
1
0
Then, the realization is:
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Prove the following Boolean identities using the laws of Boolean algebra (A + B)(A + C) = A + BC Ans. (A+B)(A+C)=A+BC LHS AA+AC+AB+BC=A+AC+AB+BC OR A((C+1)+A(B+1))+BC
Q. Describe about Minicomputers? Minicomputers, developed in the early 1960s, are high-performance, general-purpose multi user computers. These are also designed for real-tim
The extra key inserted at the end of the array is called a Sentinel is the extra key inserted at the end of the array
What is clause form and resolution?
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