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Implement the following function using 8 to 1 multiplexerY(A, B, C, D) = ∑(0,1,2,5,9,11,13,15)
Ans. We will obtain three variables B,C and D at selection lines and also A as input. Here eight inputs are given and they can be 0,1, A or A' depending upon the Boolean function.
I0
I1
I2
I3
I4
I5
I6
I7
A'
0 1 2 3 4 5 6 7
8 9 10 11 12 13 14 15
A
1
0
Then, the realization is:
No C don't have circular shift operator. (Part of the reason why that is the sizes of C's types aren't precisely described----but a circular shift makes most sense when applied to
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DETERMINE ANALYTICALY IF THE SIGNAL IS PERIODIC OR NOT - X[n] = 4Cos(Pi n)
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The output of a logic gate is 1 when all its inputs are at logic 0. The gate is either ? Ans. When all inputs of logic gate at logic 0 and output is 0. The gate is either a NOR
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