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Implementation of the Dictionary class:
int Dictionary::find_word(char *s)
{
char word[81];
for (int i = 0; i < nwords; ++i)
if (stricmp(words[i].get_word(word),s) == 0)
return i;
return -1;
}
void Dictionary::add_def(char *word, char **def)
if (nwords < Maxwords)
words[nwords].put_word(word);
while (*def != 0)
words[nwords].add_meaning(*def++);
++nwords;
int Dictionary::get_def(char *word, char **def)
char meaning[81];
int nw = 0;
int word_idx = find_word(word);
if (word_idx >= 0)
while (words[word_idx].get_meaning(nw,meaning) != 0)
def[nw] = new char[strlen(meaning)+1];
strcpy(def[nw++],meaning);
def[nw] = 0;
return nw;
To get the efficiency of Otto cycle by C/C++.
In general, Roman numerals can be converted mathematically by simply assigning a numerical value to each letter, according to the chart below, and calculating a total: M=1000 | D=5
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