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A Stack has an ordered list of elements & an array is also utilized to store ordered list of elements. Therefore, it would be very simple to manage a stack by using an array. Though, the problem along with an array is that we are needed to declare the size of the array before using it in a program. Thus, the size of stack would be fixed. However, an array & a stack are completely different data structures, an array may be utilized to store the elements of a stack. We may declare the array along a maximum size large sufficient to manage a stack. Program1 implements a stack by using an array.
Define the term - Array A fixed length, ordered collection of values of same type stored in contiguous memory locations; collection may be ordered in several dimensions.
Illustrates the program segment for Quick sort. It uses recursion. Program 1: Quick Sort Quicksort(A,m,n) int A[ ],m,n { int i, j, k; if m { i=m; j=n+1; k
Define Merge Sort Merge sort is a perfect example of a successful application of the divide and conquer method. It sorts a given array A[0...n-l] by separating it into two ha
This is the most extensively used internal sorting algorithm. In its fundamental form, it was invented by C.A.R. Hoare in the year of 1960. Its popularity lies in the easiness of i
a) Given a digraph G = (V,E), prove that if we add a constant k to the length of every arc coming out from the root node r, the shortest path tree remains the same. Do this by usin
Q. Write down an algorithm for finding a key from a sorted list using the binary search technique or method.
We have discussed that the above Dijkstra's single source shortest-path algorithm works for graphs along with non-negative edges (like road networks). Given two scenarios can emerg
Best Case: If the list is sorted already then A[i] T (n) = c1n + c2 (n -1) + c3(n -1) + c4 (n -1) = O (n), which indicates that the time complexity is linear. Worst Case:
Graph Traversal In many problems we wish to investigate all the vertices in a graph in some systematic order. In graph we often do not have any single vertex singled out as spe
Ans: A procedure to reverse the singly linked list: reverse(struct node **st) { struct node *p, *q, *r; p = *st; q = NULL; while(p != NULL) { r =q;
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