Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Illustrates about the term rectangular footings?
RECTANGULAR FOOTINGS:
The design of rectangular footings is similar to that of the square footings. The major difference is that each direction should be investigated independently. Shear is checked for two way actions in the normal manner; but one way action is checked across the shorter side only. Bending moments must be considered separately for each direction and each direction will have a different area of steel required. The reinforcing steel running in the long direction should be placed below the short direction steel so that it may have the larger effective depth to carry the larger bending moment in that direction.
Note that the distribution of reinforcement in the rectangular footings is different than that of square footings. The reinforcement in the large direction should uniformly be distributed over the shorter footing width. A part of the required reinforcement in the short direction is placed in a band equal to the short side of the footing. The portion of the total steel that should go into in this band is 2/(P +1) where, is the ratio of the long side of the footing to the short side of the footing. The remainder of the reinforcement is uniformly distributed in the outer portions of the footing. The distribution is demonstrated in below:
RECTANGULAR FOOTINGS PLAN
Drive the expression for critical pressure ratio for steam nozzle and illustrate critical pressure. Air flows in a 200cm 2 duct at a velocity of 180 m/s, a pressure of 119 KPa
i have designed a crankshaft for 3 cylinder engine i want to know how to balance it
Evaluate stress induced in rod: The two copper rods and one steel rod lie in vertical plane and support load of 50kN together as shown in figure given below. Each rod is 25 m
A simple band brake performs on a drum of 600mm in diameter that is running at 200 r.p.m. The coefficient of friction is 0.25. The brake band has a contact at 270 o one end is fas
With neat diagram illustrate the cycle of operation of four-stroke spark ignition engine. In what respects four-stroke cycle CI engine differ from that of SI engine ?
Fracture toughness of material of plate: A large thin plate carrying a crack of 70 mm at its centre is subjected to fluctuating stress cycle perpendicular to crack. s max = 7
Angle of twist is zero on the shaft: A shaft 10 m long and 100 mm diameter during its length is fixed at the ends and is subjected to two opposite torques of 8 kN-m and 10 kN-
Coefficients of friction: The coefficients of friction under the sliding supports of the door in Figure are equal to 0.30 at A and 0.20 at B. What forces P shall give the 25 k
teori heat transfer conduction
How we could build the working model of hartnell governor?
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd