Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
If the squared difference of the zeros of the quadratic polynomial x2 + px + 45 is equal to 144 , find the value of p. (Ans: ± 18).
Ans: Let two zeros are α and β where α > β
According given condition
(α - β)2 = 144
Let p(x) = x2 + px + 45
α + β = -b/a = -p /1 = - p
αβ = c/a = 45/1 = 45
now (α - β)2 = 144
(α + β)2 - 4 αβ = 144
(-p)2 - 4 (45) = 144
Solving this we get p = ± 18
199456-9029763
273.98 convert it into BCD code?
need help!
A 65 ohm resistor is connected to a power supply , a current of 2.4 amperes is drawn. what is the output voltage?
2
We want to find the integral of a function at an arbitrary location x from the origin. Thus, where I(x=0) is the value of the integral for all times less than 0. (Essenti
Describe Adding and Subtracting Square Roots? To add or subtract square roots, the radicands must be the same. If the radicands are the same, add/subtract the coefficients (the
limit x-a/|x-a| equals x-a [a]a [b]0 [c]-a [d]none 0f these
Prove: cotA/2.cotB/2.cotC/2 = cotA/2+cotB/2+cotC/2
2 times n times n divided by n
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd