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if 1/x+2, 1/x+3, 1/x+5 are in AP find x
Ans 1/x+2,1/x+3, 1/x+5 are in AP find x.
1/x+3 - 1/x+2 = 1/x+5-1/x+3
=> 1/x2 +5x+6 = 2/ x2 +8x +15
=> On solving we get x = 1
prove that s is bounded?
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