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If the roots of the equation (a-b) x 2 + (b-c) x+ (c - a)= 0 are equal. Prove that 2a=b+c. Ans: (a-b) x 2 + (b-c) x+ (c - a) = 0 T.P 2a = b + c B 2 - 4AC = 0
how do you find the unit rate?
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A triangle has vertices A (-1, 3, 4) B (3, -1, 1) and C (5, 1, 1). The area of ABC is a) 30.1 b) 82.1 c) 9.1 d) 52.1
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if b+c=3a then the value of cotB/2.cotC/2 is equal to
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