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If hydrogen atom is in an energy level represented by n=4,how many spectral lines are possible in its emission spectrum?
Ans) There is a formula for this i.e
[ (n2-n1+1)(n2-n1) / 2 ] So if acc. to your question n1=1 and n2=4 then the answer is 6
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2p orbitals have : (1) n=1, l=2 (2) n=1, l=0 (3) n=2 l=1 (4)n=2, l=0 Ans: n=2 l=1
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