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If hydrogen atom is in an energy level represented by n=4,how many spectral lines are possible in its emission spectrum?
Ans) There is a formula for this i.e
[ (n2-n1+1)(n2-n1) / 2 ] So if acc. to your question n1=1 and n2=4 then the answer is 6
zinc+copper(ll) chloride
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history of this reaction.is any ligand is needed for the reaction?
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The total number of valence electrons in 4.2 gm N - 3 of ion is ( N A is the Avogadro's number): (1) 1.6N A (2) 3.2N A
caco3
Which of the following compounds is ionic: (1) Kl (2) CH 4 (3) Diamond (4) H 2 Ans: Kl
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