How to solve the checking problem, Theory of Computation

Assignment Help:

The objective of the remainder of this assignment is to get you thinking about the problem of recognizing strings given various restrictions to your model of computation. We will work with whatever representation of an algorithm you are comfortable with (C or Pascal or, perhaps, some form of pseudo-code-just make sure it is unambiguous). Don't get too carried away with this. You only have a short time to work on it. The goal is primarily to think about this stu?, not to agonize over it. Whatever you do, don't turn it into a programming assignment; running code is not a bonus in this case.

In all of the problems we will assume the same basic machine:

• The program is read-only (it can't be modi?ed, you might even think of it as being hard-wired).

• For the sake of uniformity, let's assume the following methods for accessing the input:

- input(), a function that returns the current input character. You can use this in forms like

i ← input(), or

if (input() = ‘a' ) then . . . , or

push(input()).

This does not consume the character; any subsequent calls to input() prior to a call to next() will return the same character. You may assume that input() returns a unique value EOF if all of the input has been consumed.

- next(), a function that bumps to the next position in the input.

This discards the previous character which cannot be re-read. You can either assume that it returns nothing or that it returns TRUE in the case the input is not at EOF and FALSE otherwise.


Related Discussions:- How to solve the checking problem

Operator p, implementation of operator precedence grammer

implementation of operator precedence grammer

Computation of a dfa or nfa, Computation of a DFA or NFA without ε-transiti...

Computation of a DFA or NFA without ε-transitions An ID (q 1 ,w 1 ) computes (qn,wn) in A = (Q,Σ, T, q 0 , F) (in zero or more steps) if there is a sequence of IDs (q 1

Exhaustive search, A problem is said to be unsolvable if no algorithm can s...

A problem is said to be unsolvable if no algorithm can solve it. The problem is said to be undecidable if it is a decision problem and no algorithm can decide it. It should be note

Concatenation, We saw earlier that LT is not closed under concatenation. If...

We saw earlier that LT is not closed under concatenation. If we think in terms of the LT graphs, recognizing the concatenation of LT languages would seem to require knowing, while

Describe the algorithm and draw the transition diagram, 1. Simulate a TM wi...

1. Simulate a TM with infinite tape on both ends using a two-track TM with finite storage 2. Prove the following language is non-Turing recognizable using the diagnolization

Project, can you plz help with some project ideas relatede to DFA or NFA or...

can you plz help with some project ideas relatede to DFA or NFA or anything

Computations of sl automata, We will specify a computation of one of these ...

We will specify a computation of one of these automata by specifying the pair of the symbols that are in the window and the remainder of the string to the right of the window at ea

Finite-state automaton, Paths leading to regions B, C and E are paths which...

Paths leading to regions B, C and E are paths which have not yet seen aa. Those leading to region B and E end in a, with those leading to E having seen ba and those leading to B no

Local suffix substitution closure, The k-local Myhill graphs provide an eas...

The k-local Myhill graphs provide an easy means to generalize the suffix substitution closure property for the strictly k-local languages. Lemma (k-Local Suffix Substitution Clo

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd