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Use L''hopital''s rule since lim X-->0 1-cos(x)/1-cos(4x) is in the indeterminate form 0/0 when we apply the limtso by l''hoptital''s rule differentiate the numerator and denominatiorso we get lim x-->0 sin(x)/4sin(4x) again in the indeterminate form when we apply limit so again use l''hopitals'' rulelim x-->0 cos(x)/16cos(4x) now if u apply the limit we get it as 1/16so lim x--->0 1-cos(x)/1-cos(4x) = 1/16
R is called as a transitive relation if (a, b) € R, (b, c) € R → (a, c) € R In other terms if a belongs to b, b belongs to c, then a belongs to c. Transitivity be uns
tanx dx
Suppose S = {vi} and T = {ti} are "easy" sets of knapsak weight. Also, P and q are primes p > ?Si and q > ?ti. We can combine S and T into a signle set of knapsack weight as follow
finite or infinite 1]A={4,5,6,....}
Definition 1. We say that f(x) consist an absolute (or global) maximum at x = c if f ( x ) ≤ f (c ) for every x in the domain we are working on. 2. We say that at x = c ,
if triangle abc is similar to def and ab/de=3/4 find the ratio af their perimeter and area
1. Give some Class 4 children around you problems like 15 x 6 to do dentally. Interact with them to find out the different strategies they use for doing it, and note these down.
INSTRUCTIONS: Construct a regular proof to derive the conclusion of the following argument: 1. H v (~T > R) 2. Hv (E > F) 3. ~T v E 4. ~H & D / R v F INSTRUCTIONS: Con
nC6:n-3C3=91:4
2+4
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