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How to catch multiple exceptions explain with example?
If multiple blocks match the exception type, the first block in which matches the kinds of the exception catches it. public class HelloThere {
public static void main(String[] args) { int repeat; try { // possible NumberFormatException and ArrayIndexOutOfBoundsException repeat = Integer.parseInt(args[0]); // possible ArithmeticException int n = 2/repeat; // possible StringIndexOutOfBoundsException String s = args[0].substring(5); } catch (NumberFormatException e) { // print an error message System.err.println("Usage: java HelloThere repeat_count" ); System.err.println( "where repeat_count is the number of times to say Hello" ); System.err.println("and given as an integer like 1 or 7" ); return; } catch (ArrayIndexOutOfBoundsException e) { // pick a default value repeat = 1; } catch (IndexOutOfBoundsException e) { // ignore it } catch (Exception e) { // print an error message and exit System.err.println("Unexpected exception"); e.printStackTrace(); return; } for (int i = 0; i < repeat; i++) { System.out.println("Hello"); } }
}It's rare to catch a general Error or Throwable because it's actually hard to clean up after them in the general case.
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I need to get how to start the java program to evaluate the simillarity.
You may call function from any other place into your JavaScript code. After the function is executed, the control goes back to other script which called it. alert('Example 1: t
How do you set up a nested class?
YES. JSP technology is extensible by the development of custom actions, or tags, which are encapsulated in tag libraries. #question..
Question Based on the program fragment below, rewrite the outer for loop using: a. while loop b. repeat..until loop
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