Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Q. Ca+2 = 20 ppm, Mg+2 = 25 ppm, CO2 = 30 ppm, HCO-3 = 150, K+ = 10 ppm. Calculate the lime (87% pure) and soda (91% pure) required softening 1 million litters of water sample.
Ans.
Calculation of CaCO3 equivalent of given impurities:
S.NO
substances
Amount of substances in mg/L
Multiplication factor
CaCO3 equivalent mg/L
1.
Ca++
20 ppm
100/40
100/40*20 =50
2.
Mg++
25 ppm
100/24
100/24*25 = 104.16
3.
CO2
30 ppm
100/44
100/44*30 = 68.181
4.
HCO-3
150 ppm
100/122
100/122*150 = 122.95
5.
K+
10 ppm
Not produce hardness
Lime required:
74/100[Mg++ + CO2 + HCO-3 as CaCO3 equivalent] mg/L *Volume of water*100/%purity
74/100[104.16 + 68.181 + 122.95] mg/L*1000000l*100/86
74/100[295.29] mg/L * 100000*100/87
= 251.16*106 mg
= 251.16*106 mg*1Kg/106
= 251.16
Soda required = 106/100[50 + 104.16 – 122.95] mg/L *1000000*100/91
= 100/106[31.21] mg/L*106*100/91
= 36.35*106 mg
= 36.35*106 mg*1Kg/106
= 36.35Kg
perkin ring closure reaction of melonic ester with C2H5O-Na+
Question: (i) List the different members of the marine mammalian groups. (ii) Explain the term "stranding" and give some reasons why cetaceans strand? (iii) Cetacean
The transition metal complexes are known to be paramagnetic in character. CFT helps us to understand the magnetic properties in terms of magnetic susceptibility measurements. The m
The four quantum numbers of the outermost orbital of K (atomic no. =19) are: (1) n= 2, l= 0, m=0, s= +1/2 (2) n= 4, l= 0, m=0, s= +1/2 (3) n= 3, l= 1,
Write an equation that shows the formation of the selenide ion from a neutral selenium atom
Q. Illustrate Law of Equilibrium and Equilibrium Constants? Ans. The general equation for a reversible reaction is given by aA + bB -> cC + dD The law of equilibrium
P= 10.5atm v= 2.06L T= 298K p= 5.21atm v= 6.15 t= ? what is t?
Hofmann elimination, also called as Exhaustive methylation, is a process where an amine is reacted to create a tertiary amine and an alkene by treatment with excess methyl iodide f
advantages and disadvantages of westron
explain the synthesis of freon and westron i need only the synthesis of those coompound
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd