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Q. How to Access the Disk Data?
Disks operate is semi-random mode of operation and generally referenced block wise. The data access time on a disk comprises two major components:
In addition to seek and latency time the time taken to transfer a (read/write) block of words can be considered however normally it is too small in comparison to seek time and latency and in general disk access time is concerned to be sum of seek time and latency time. Because access time of disks is large so it is advisable to read a sizeable part of data in a single go and so disks are referenced block wise. As a matter of fact you will find that in most of computer system input/output involving disk is given a very high priority. Fundamental reason for such priority is latency time which is needed once the block which is to be read passes below read-write head. It may take time of order of milliseconds to do it again, in turn delaying Input /Output and lowering performance of system.
Prepare the Relational Tables to signify the following situation, which is defined by means of text and an Entity Relationship Diagram. Note: Do not attempt to vary the ERD. Yo
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consider the 8 bit floating point format including support for normalised nimbers and nonnumeric values.it included 3 bits for mantissa and 4 bitys for excess 7 exponent
What courses draught in a simple pendulum experiment
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Speicified the following piece of code: int i = 1; int j = 4; while (i { if (i%3 == 0) i+=3; else i+=4; if (j%2 == 0) j*=4; els
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