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Q. How to Access the Disk Data?
Disks operate is semi-random mode of operation and generally referenced block wise. The data access time on a disk comprises two major components:
In addition to seek and latency time the time taken to transfer a (read/write) block of words can be considered however normally it is too small in comparison to seek time and latency and in general disk access time is concerned to be sum of seek time and latency time. Because access time of disks is large so it is advisable to read a sizeable part of data in a single go and so disks are referenced block wise. As a matter of fact you will find that in most of computer system input/output involving disk is given a very high priority. Fundamental reason for such priority is latency time which is needed once the block which is to be read passes below read-write head. It may take time of order of milliseconds to do it again, in turn delaying Input /Output and lowering performance of system.
Q. Pros and Cons of general purpose register architecture? General Purpose Register Architecture: Pros and Cons Registers can be employed to store variables as it decrea
Q. Explain about Theta Notation? Theta Θ Notation : The set Θ (g(n)) comprises all functions f(n) for that there exist positive constants c1,c2 such that f(n) is squeezed in b
State The advantages of specifying parameter assignments using defparam are: - This method always has precedence over specifying parameters at the instance of instantiation.
What are the elements of Analysis model? i. Data Dictionary ii. Entity Relationship Diagram iii. Data Flow Diagram iv. State Transition Diagram v. Control Specifica
Difference between ipv4 and ipv6
Terms in Propositional model: There in first-order logic allows us to talking about properties of objects that the first job for our model (Δ, Θ) is to assign a meaning to the
What is a decoder? Draw the logic circuit of a 3 line to 8 line decoder and explain its working. Ans. Decoder: it is a combinational logic circuit which converts Binary words
One Erlang is equal to (A) 3600 CCS (B) 36 CCS (C) 60 CCS (D) 24 CCS Ans: One Erlang is equivalent to 3600 CCS.
RST 4.5 is known as TRAP.
Interrupt Signal Interconnection Network (ISIN): When a processor wish to transmit an interruption to another processor, then this interrupt initially goes to ISIN, by which it
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