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Q. How to Access the Disk Data?
Disks operate is semi-random mode of operation and generally referenced block wise. The data access time on a disk comprises two major components:
In addition to seek and latency time the time taken to transfer a (read/write) block of words can be considered however normally it is too small in comparison to seek time and latency and in general disk access time is concerned to be sum of seek time and latency time. Because access time of disks is large so it is advisable to read a sizeable part of data in a single go and so disks are referenced block wise. As a matter of fact you will find that in most of computer system input/output involving disk is given a very high priority. Fundamental reason for such priority is latency time which is needed once the block which is to be read passes below read-write head. It may take time of order of milliseconds to do it again, in turn delaying Input /Output and lowering performance of system.
1. (a) Given a baseband bus with station 1 located at 10m, station 2 located at 1000m, and station 3 located at 1010 meters (see diagram above). If the data rate of the bus is 10 M
a) Total available bandwidth = 1 Mbps = 1000 Kbps Each user requires send data at the rate of = 500 kbps As it is circuit switched network we have to dedicate the bandwidth So the
Perform the - 48 - 23 operations using the 2's complement method. Ans. - 48 - 23 = - 48 + (-23) -48 = 1 1 0 1 0 0 0 0 -23 = 1 1 1 0 1 0 0 1 = -71
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Convert 2222 in Hexadecimal number ? Ans. = 8AE
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Give difference between compiler and interpreter. Compiler: It is a translator for machine independent HLL as FORTRAN and COBOL etc. Interpreter: It analysis the source
Show System call for cloning. Standard form of Clone function is as follows: Int clone (Int (*FN) (), void *child stack, Int flag, intargs,); Parameter FN is Pointer fro
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