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Q. How to Access the Disk Data?
Disks operate is semi-random mode of operation and generally referenced block wise. The data access time on a disk comprises two major components:
In addition to seek and latency time the time taken to transfer a (read/write) block of words can be considered however normally it is too small in comparison to seek time and latency and in general disk access time is concerned to be sum of seek time and latency time. Because access time of disks is large so it is advisable to read a sizeable part of data in a single go and so disks are referenced block wise. As a matter of fact you will find that in most of computer system input/output involving disk is given a very high priority. Fundamental reason for such priority is latency time which is needed once the block which is to be read passes below read-write head. It may take time of order of milliseconds to do it again, in turn delaying Input /Output and lowering performance of system.
VuGen have two options to help debug Vuser scripts-the Run Step by Step command and breakpoints. The Debug settings in the Options dialog box permit us to verify the extent of the
Q. Interconnection network in the form of a Linear Array? The sorting problem particularly selected is bubble sort and interconnection network may be represented as n processor
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Q. Concurrently read exclusively write? It's one of the models based on PRAM. In this model, processors access the memory location simultaneously for reading whereas exclusivel
For the 8-bit bidirectional register in Figure 3, verify the status of the register after every clock pulse for the LEFT RIGHT /control waveform given. A HIGH on this input permits
advantages and disadvantages of layered architecture in computer network.
Difference between static and dynamic RAM. Draw the circuits of one cell of each and explain its working. Ans: Differentiation among Static RAM and Dynamic RAM: Static
(a) Explain in a few sentences the difference between a natural frequency and a resonant frequency. Also clarify why for a specific system or component these frequencies may diff
Open addressing: The easiest way to resolve a collision is to begin with the hash address and do a sequential search by the table for an empty location. The idea is to place the
Logic for multiplexer tree
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