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Kevin invested $4,000 in an account which earns 6% interest per year and $x in a different account that earns 8% interest per year. How much is invested at 8% if the total amount of interest earned annually is $405.50?
Let x = the amount invested at 8% interest. Since the total interest is $405.50, use the equation 0.06(4,000) + 0.08x = 405.50. Simplify the multiplication: 240 + 0.08x = 405.50. Subtract 240 from both sides: 240 - 240 + 0.8x = 405.50 - 240; simplify: 0.08x = 165.50. Divide both sides by 0.08: 0.08x/0.08=165.50/0.08. Thus, x = $2,068.75, that is the amount invested at 8% interest.
If OA = OB = 14cm, ∠AOB=90 o , find the area of shaded region. (Ans:21cm 2 ) Ans: Area of the shaded region = Area of ? AOB - Area of Semi Circle = 1/2 x 14 x
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use the simplex method to solve the following lp problem. max z = 107x1 + x2 + 2x3 subject to 14x1 + x2 - 6x3 + 3x4 = 7 16x1 + x2 - 6x3 3x1 - x2 - x3 x1,x2,x3,x4 > = 0
1) Compute the center of mass of the solid of unit density 1 bounded (in spherical coordinates) by p=1 and by φ is greater than or equal 0 and less than or equal pi/4
break even analysis problem and solutions
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